 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | Joseph Benjamin Rider - Engineering - 1901 - 546 pages
...square in the left-hand period, and write its root at the right in the form of a quotient in division. Subtract this square from the left-hand period, and to the remainder annex the next period to form a dividend. Double the part of the root already found for a trial divisor. Find how many times... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...the given number into periods of three figures each. root. Subtract the cube of this number from the period, and to the remainder annex the next period for a dividend. 3. Square the part of the root found, multiply the product by 300, and write the result ou the left... | |
 | George Edward Atwood - Arithmetic - 1902 - 168 pages
...1521 10304 RULE. — Separate the number into periods of two figures each, beginning at the right. Find the greatest square in the left-hand period,...found for a partial divisor. Divide the dividend, omitting the right-hand figure, by the partial divisor, and annex the quotient to the root and also... | |
 | Edward Gideon - 1902 - 272 pages
...period, and place its root for the first figure of the required root. Subtract the square of this figure from the left-hand period, and to the remainder annex the next period, for a dividend. III. Double the root already found, regarded as tens, for a trial divisor; find how often it is contained... | |
 | Léon Stefflre - Arithmetic - 1902 - 230 pages
...period thus formed and place it under, and its root over, such period ; 8. Subtract this cube from said period and to the remainder annex the next period for a dividend, ie, carry said remainder to the next period; e. Multiply the square of the part of the root found by... | |
 | Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...square in the left-hand period, and write its root at the right in the form of a quotient in division. Subtract this square from the left-hand period, and to the remainder annex the next period to form a dividend. Double the part of the root already found for a trial divisor. Find how many times... | |
 | Jacob Henry Minick, Clement Carrington Gaines - Business mathematics - 1904 - 412 pages
...left-hand period, and write it as tlie first figure of the root. Cube this root and subtract the result from the left-hand period, and to the remainder annex the next period for a dividend. Take three times the square of the root already, found, for a trial divisor ; divide the dividend,... | |
 | Benjamin Franklin Sisk - Arithmetic - 1905 - 224 pages
...left-hand period and write its root for the first figure in the root. 3. Subtract the cube from the period, and to the remainder annex the next period for a dividend. 4. For a trial divisor, write three times the square of the root found, considered as tens. 5. Divide,... | |
 | William James Milne - Arithmetic - 1906 - 364 pages
...root. /Square this root, subtract the result from the left-hand period, and annex to the remainder the next period for a dividend. Double- the root already found, for a partial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient, or quotient diminished,... | |
 | William James Milne - Arithmetic - 1906 - 364 pages
...required root. Square this root, subtract the result from the left-hand period, and annex to the remainder the next period for a dividend. Double. the root already found, for a partial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient, or quotient diminished,... | |
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