 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | Stoddard A. Felter - Arithmetic - 1864 - 430 pages
...the left from units' place. II. Find the root of the left hand period; subtract its square from the period; and to the remainder annex the next period for a dividend. III. Multiply the root found by 20 for a trial divisor ; divide and take the quotient for the next... | |
 | W H. Wingate - 1865 - 150 pages
...the left hand, and place it to the right of the given quantity ; subtract its square from the first period, and to the remainder annex the next period for a dividend — find a divisor by doubling the root figure already found — see how often this is contained in... | |
 | James Stewart Eaton - Arithmetic - 1867 - 358 pages
...trial the greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period, and to the remainder annex the next period fur a dividend. 3. Square the root figure, annex two ciphers and multiply tltis result by 3 fur a TRIAL... | |
 | William Frothingham Bradbury - Algebra - 1868 - 270 pages
...Find the greatest cube in the left-hand period, and place its root at tJie rigM. Subtract this cube from the left-hand period, and to the remainder annex the next period for a dividend. Square the root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
 | John Groesbeck - Arithmetic - 1868 - 358 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
 | John Groesbeck - Arithmetic - 1868 - 350 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
 | Stoddard A. Felter - Arithmetic - 1868 - 360 pages
...toward the left from units' place. II. Find the root of the left Jmnd period, subtract its cube from the period, and to the remainder annex the next period for a dividend. IIL Multiply the square of* the root found, by 300, for a trial divisor ; divide and take the quotient... | |
 | William Frothingham Bradbury - Algebra - 1868 - 264 pages
...cube in the lef1-hand period, and place its root at the right. Subtract this cube from the lef1-hand period, and to the remainder annex the, next period for a dividend. Square the root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1869 - 332 pages
...cube is contained in the lefthand period, and write it in the root ; subtract the cube of this root from the left-hand period, and to the remainder annex the next period for a dividend. Take three times the square of the root found, regarded as tens, for a trial divisor ; divide the dividend... | |
 | Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...figure of the root. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor, and find how often the divisor is contained in the dividend, exclusive of the right-hand figure,... | |
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