Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Stoddard A. Felter - Arithmetic - 1864 - 428 pages
...the left from units' place. II. Find the root of the left hand period; subtract its square from the **period; and to the remainder annex the next period for a dividend.** III. Multiply the root found by 20 for a trial divisor ; divide and take the quotient for the next... | |
| W H. Wingate - 1865 - 150 pages
...the left hand, and place it to the right of the given quantity ; subtract its square from the first **period, and to the remainder annex the next period for a dividend** — find a divisor by doubling the root figure already found — see how often this is contained in... | |
| James Stewart Eaton - Arithmetic - 1867 - 358 pages
...trial the greatest cube in the left-hand period, place its root as in square root, subtract the cube **from the left-hand period, and to the remainder annex the next period** fur a dividend. 3. Square the root figure, annex two ciphers and multiply tltis result by 3 fur a TRIAL... | |
| William Frothingham Bradbury - Algebra - 1868 - 270 pages
...Find the greatest cube in the left-hand period, and place its root at tJie rigM. Subtract this cube **from the left-hand period, and to the remainder annex the next period for a dividend.** Square the root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
| John Groesbeck - Arithmetic - 1868 - 358 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number **from the left-hand period, and to the remainder annex the next period** of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
| John Groesbeck - Arithmetic - 1868 - 350 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number **from the left-hand period, and to the remainder annex the next period** of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
| Stoddard A. Felter - Arithmetic - 1868 - 360 pages
...toward the left from units' place. II. Find the root of the left Jmnd period, subtract its cube from the **period, and to the remainder annex the next period for a dividend.** IIL Multiply the square of* the root found, by 300, for a trial divisor ; divide and take the quotient... | |
| William Frothingham Bradbury - Algebra - 1868 - 264 pages
...cube in the lef1-hand period, and place its root at the right. Subtract this cube from the lef1-hand **period, and to the remainder annex the, next period for a dividend.** Square the root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
| Henry Bartlett Maglathlin - Arithmetic - 1869 - 332 pages
...cube is contained in the lefthand period, and write it in the root ; subtract the cube of this root **from the left-hand period, and to the remainder annex the next period for a dividend.** Take three times the square of the root found, regarded as tens, for a trial divisor ; divide the dividend... | |
| Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...figure of the root. Subtract this square number from the first period, and to the remainder bring down **the next period for a dividend. Double the root already found for a** divisor, and find how often the divisor is contained in the dividend, exclusive of the right-hand figure,... | |
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