 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | William James Milne - Arithmetic - 1907 - 616 pages
...required root. Square this root, subtract the result from the left-hand period, and annex to the remainder the next period for a dividend. Double the root already found, for a partial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient, or quotient diminished,... | |
 | George Augustus Walton, Stanley Harry Holmes - Arithmetic - 1909 - 316 pages
...greatest square in the left-hand period, and write its square root as the first term of the root. 3. Subtract this square from the left-hand period and...the remainder annex the next period for a dividend. 4. Double the. part of the root already found considered as tens for a trial divisor, and by this divide... | |
 | George Augustus Walton, Stanley Harry Holmes - Arithmetic - 1909 - 316 pages
...greatest square in the left-hand period, and write its square root as the first term of the root. 3. Subtract this square from the left-hand period and...the remainder annex the next period for a dividend. 4. Double the, part of the root already found considered as tens for a trial divisor, and by this divide... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1909 - 276 pages
...and write its root for the first figure of the required root. Square this root, subtract the result from the left-hand period, and to the remainder annex the next period for a dividend. For a partial divisor double the root already found, considered as tens, and divide the dividend by... | |
 | Wilbur Fisk Nichols - 1910 - 236 pages
...square in the left-hand period, and write its root above the period as the first figure of the root. 3. Subtract this square from the left-hand period and...the remainder annex the next period for a dividend. 4. Double the root already found for a trial divisor. Divide by the trial divisor, writing the quotient... | |
 | DeForest A. Preston, Edward Lawrence Stevens - Arithmetic - 1910 - 380 pages
...period and write it as the first figure of the answer. 3. Subtract the square of this first root figure from the left-hand period, and to the remainder annex the next period* times the dividend, exclusive of its right-hand figure, will contain the result. 5. Write the number... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1911 - 396 pages
...period and write its root for the first figure of the required root. Cube this root, subtract the result from the left-hand period, and to the remainder annex the next period fur a dividend. For a partial divisor, take three times the square of the root alrcady found, considered... | |
 | Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...period, and write its root for the first figure of the required root. Subtra(t the cube of this figure from the left-hand period and to the remainder annex the next period to form a dividend. Divide this dividend by the partial divisor, which is 3 times the square of the... | |
 | George Albert Wentworth, David Eugene Smith - Arithmetic - 1914 - 396 pages
...and write its root for the first figure of the required root. Square this root, subtract the result from the left-hand period, and to the remainder annex the next period for a dividend. Divide the new dividend thus obtained by twice the part of the root already found. Annex the figure... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...root. /Square this root, subtract the result from the left-hand period, and annex to the remainder the next period for a dividend. Double the root already found, for a partial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient, or quotient diminished,... | |
| |
