 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | John Groesbeck - Business mathematics - 1871 - 370 pages
...greatest square in the left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...in the left-hand period, and place its root on the right as the first root-figure. Subtract its cube from the left-hand period, and to the remainder annex the next period for a dividend. IIL Square the first root-figure, annex two ciphers, multiply the result by 3, and place it on the... | |
 | John Groesbeck - 1872 - 374 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find hov> many times the divisor... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1873 - 362 pages
...square is contained in the '.eft-hand period, and write it in the root ; subtract the square of this from the left-hand period, and to the remainder annex the next period for a dividend. Take twice the root found, regarded as tens, for a trial divisor ; divide the dividend by it, and write... | |
 | William Frothingham Bradbury - 1875 - 280 pages
...Subtract the square of this root figure from the left-hand period, and to the remainder annex tlie next period for a dividend. Double the root already found for a TRIAL DIVISOR, and, omitting the right-hand figure of the dividend, divide, and place the quotient... | |
 | Benjamin Greenleaf - Arithmetic - 1876 - 344 pages
...figure of the root. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor, and find how often the divisor is contained in the dividend, exclusive of the right-hand figure,... | |
 | Edward Olney - Arithmetic - 1876 - 322 pages
...root of the highest cube in the left-hand period as the first figure in the root, subtract this cube from the left-hand period and to the remainder annex the next period, forming a new dividend. 3. Take 3 times the square of the root already found, regarded as tens, as... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...left-hand period, and write its root as a quotient in division. Subtract the'square of this figure from the left-hand period, and to the remainder annex the next period. Use this result as a dividend, and for a divisor double the figure in the root. See how often this... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...contained in the first left-hand period, for the first figure of the root. Subtract the cube of this figure from the left-hand period, and to the remainder annex the next period for a dividend. For a trial divisor, annex one cipher to the figure of the root just found, square the number thus... | |
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