Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...in the left- hand period, and place its root at the right. Subtract the square of this root figure **from the left-hand period, and to the remainder annex...for a dividend. Double the root already found for a** TIUAL DIVISOR, and, omitting tia right-hand figure of the dividend, divide, and place the quotient... | |
| James William Nicholson - Arithmetic - 1889 - 408 pages
...square in the left hand period, and place its root on the right for the first root-figure. Subtract its **square from the left-hand period, and to the remainder annex the next period for a dividend.** III. Double the part of the root already found, and place it on the left for a trial divisor; divide... | |
| William Frothingham Bradbury - Algebra - 1889 - 444 pages
...Find the greatest cube in the left-hand period, and place its root at the right. Subtract this cube **from the left-hand period, and to the remainder annex the •next period for a dividend.** Square tl1e root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
| John Groesbeck - 1891 - 426 pages
...period, and place its root for the first figure of the required root. Subtract the square of this figure **from the left-hand period, and to the remainder annex the next period for a dividend.** 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend,... | |
| William James Milne - Arithmetic - 1892 - 480 pages
...root. Square this root and subtract the result from the left-hand period, and annex to the remainder **the next period for a dividend. Double the root already found for a partial divisor,** and by it divide the dividend, disregarding the right-hand figure. The quotient or quotient diminished... | |
| Henry B. Maglathlin - 1894 - 368 pages
...cube is contained in the lefthand period, and write it in the root; subtract the cube of this root **from the left-hand period, and to the remainder annex the next period for a dividend.** Take three times the square of the root found, regarded as tens, for a trial divisor; divide the dividend... | |
| George Edward Atwood - Arithmetic - 1894 - 396 pages
...the left-hand period, and write its cube root for the first figure of the root. Subtract this cube **from the left-hand period, and to the remainder annex the next period for a, dividend.** Square the root already found, multiply the square by 3, and to the product annex two ciphers for a... | |
| William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...greatest cube in the left-hand period write its root at the right of the given number, subtract the cube **from the left-hand period, and to the remainder annex the next period for a dividend.** 3. Square the root figure, annex two ciphers, and multiply this resu1t by three for a trial divisor... | |
| Bothwell Graham - Arithmetic - 1895 - 238 pages
...of a quotient at the right of the number. Subtract the square of this root figure from the lefl-hand **period, and to the remainder annex the next period for a dividend.** Take twice the figure of the root found for a trial divisor; divide the dividend, omitting the last... | |
| George Edward Atwood - Arithmetic - 1899 - 388 pages
...the left-hand period, and write its cube root for the jirst figure of the root. Subtract this cube **from the left-hand period, and to the remainder annex the next period for a. dividend.** Square the root already found, multiply the square by 8, and to the. product annex two ciphers for... | |
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