 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...in the left- hand period, and place its root at the right. Subtract the square of this root figure from the left-hand period, and to the remainder annex...for a dividend. Double the root already found for a TIUAL DIVISOR, and, omitting tia right-hand figure of the dividend, divide, and place the quotient... | |
 | James William Nicholson - Arithmetic - 1889 - 408 pages
...square in the left hand period, and place its root on the right for the first root-figure. Subtract its square from the left-hand period, and to the remainder annex the next period for a dividend. III. Double the part of the root already found, and place it on the left for a trial divisor; divide... | |
 | William Frothingham Bradbury - Algebra - 1889 - 444 pages
...Find the greatest cube in the left-hand period, and place its root at the right. Subtract this cube from the left-hand period, and to the remainder annex the •next period for a dividend. Square tl1e root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISOR ;... | |
 | John Groesbeck - 1891 - 426 pages
...period, and place its root for the first figure of the required root. Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend,... | |
 | William James Milne - Arithmetic - 1892 - 480 pages
...root. Square this root and subtract the result from the left-hand period, and annex to the remainder the next period for a dividend. Double the root already found for a partial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient or quotient diminished... | |
 | Henry B. Maglathlin - 1894 - 368 pages
...cube is contained in the lefthand period, and write it in the root; subtract the cube of this root from the left-hand period, and to the remainder annex the next period for a dividend. Take three times the square of the root found, regarded as tens, for a trial divisor; divide the dividend... | |
 | George Edward Atwood - Arithmetic - 1894 - 396 pages
...the left-hand period, and write its cube root for the first figure of the root. Subtract this cube from the left-hand period, and to the remainder annex the next period for a, dividend. Square the root already found, multiply the square by 3, and to the product annex two ciphers for a... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...greatest cube in the left-hand period write its root at the right of the given number, subtract the cube from the left-hand period, and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers, and multiply this resu1t by three for a trial divisor... | |
 | Bothwell Graham - Arithmetic - 1895 - 238 pages
...of a quotient at the right of the number. Subtract the square of this root figure from the lefl-hand period, and to the remainder annex the next period for a dividend. Take twice the figure of the root found for a trial divisor; divide the dividend, omitting the last... | |
 | George Edward Atwood - Arithmetic - 1899 - 388 pages
...the left-hand period, and write its cube root for the jirst figure of the root. Subtract this cube from the left-hand period, and to the remainder annex the next period for a. dividend. Square the root already found, multiply the square by 8, and to the. product annex two ciphers for... | |
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