Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Samuel Mecutchen - Arithmetic - 1880 - 244 pages
...product falls under the first left-hand period of the given number. Subtract this product from this first **left-hand period, and to the remainder annex the next period for a** new dividend. Add the figure of the root just found to the amount in the first column, multiply the... | |
| H. Bryant - 1881 - 574 pages
...place its root on the right as the highest order of the root. 3. Subtract the square of the root figure **from the left-hand period, and to the remainder annex the next period for a dividend.** 4. Double the part of the root already found for a trial divisor, consider how many times it is contained... | |
| William Frothingham Bradbury - 1881 - 404 pages
...the left-hand period, write its root at the right of the given number, subtract the cube from tlie **left-hand period, and to the remainder annex the next period for a dividend.** 3. Square the root figure, annex two ciphers, and multiply this result by three for a trial divisor... | |
| Arithmetic - 1882 - 392 pages
...left-hand period, and write it for the first figure of the root. 2. Subtract this square from the first **period; and to the remainder annex the next period for a dividend.** III. To find the second figure of the root:— 1. Double the root already found, considered as tens,... | |
| Henry Bartlett Maglathlin - Arithmetic - 1882 - 400 pages
...cube in the left period, and place its root at the right. Subtract the cube of this root from the left **period, and to the remainder annex the next period for a dividend.** Annex a cipher to the root already found, and take three times its square for a trial divisor. Divide... | |
| Zalmon Richards - Arithmetic - 1885 - 132 pages
...than one figure. Take its square root for the first figure of the root. Subtract the square thus found **from the left-hand period, and to the remainder annex the next period for a dividend.** 3d. — Find a trial divisor by doubling the root found, and then find how many times it is contained... | |
| James William Nicholson - Arithmetic - 1885 - 348 pages
...period, and place its root on the right for the first rcot-figure. Subtract its cube from the left hand **period, and to the remainder annex the next period for a dividend.** Square the part of the root already found, multiply the result by 3, annex two ciphers, and place it... | |
| Christian Brothers - Arithmetic - 1888 - 482 pages
...two figures each. II. Having found, the root of the left-hand, period,, subtract its square from the **period,, and to the remainder annex the next period for a dividend.** III. Divide the dividend, omitting the last figure, by double the root already found, and annex the... | |
| Edward Albert Bowser - Algebra - 1888 - 876 pages
...first figure of the root ; subtract its square from the first period, and to the remainder bring doivn **the next period for a dividend. Double the root already found for a** trial divisor, and see how many times it is contained in the dividend, omitting the last figure, and... | |
| Algebra - 1888 - 494 pages
...root will be the cube root of the greatest cube contained in the left-hand period. Subtract this cube **from the left-hand period, and to the remainder annex the next period** to form a dividend. III. For a trial divisor take three times the square of the root figure, regarded... | |
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