 Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | Samuel Mecutchen - Arithmetic - 1880 - 292 pages
...product falls under the first left-hand period of the given number. Subtract this product from this first left-hand period, and to the remainder annex the next period for a new dividend. Add the figure of the root just found to the amount in the first column, multiply the... | |
 | H. Bryant - 1881 - 574 pages
...place its root on the right as the highest order of the root. 3. Subtract the square of the root figure from the left-hand period, and to the remainder annex the next period for a dividend. 4. Double the part of the root already found for a trial divisor, consider how many times it is contained... | |
 | William Frothingham Bradbury - 1881 - 404 pages
...the left-hand period, write its root at the right of the given number, subtract the cube from tlie left-hand period, and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers, and multiply this result by three for a trial divisor... | |
 | Arithmetic - 1882 - 392 pages
...left-hand period, and write it for the first figure of the root. 2. Subtract this square from the first period; and to the remainder annex the next period for a dividend. III. To find the second figure of the root:— 1. Double the root already found, considered as tens,... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1882 - 398 pages
...cube in the left period, and place its root at the right. Subtract the cube of this root from the left period, and to the remainder annex the next period for a dividend. Annex a cipher to the root already found, and take three times its square for a trial divisor. Divide... | |
 | Zalmon Richards - Arithmetic - 1885 - 136 pages
...than one figure. Take its square root for the first figure of the root. Subtract the square thus found from the left-hand period, and to the remainder annex the next period for a dividend. 3d. — Find a trial divisor by doubling the root found, and then find how many times it is contained... | |
 | James William Nicholson - Arithmetic - 1885 - 348 pages
...period, and place its root on the right for the first rcot-figure. Subtract its cube from the left hand period, and to the remainder annex the next period for a dividend. Square the part of the root already found, multiply the result by 3, annex two ciphers, and place it... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...two figures each. II. Having found, the root of the left-hand, period,, subtract its square from the period,, and to the remainder annex the next period for a dividend. III. Divide the dividend, omitting the last figure, by double the root already found, and annex the... | |
 | Edward Albert Bowser - Algebra - 1888 - 868 pages
...first figure of the root ; subtract its square from the first period, and to the remainder bring doivn the next period for a dividend. Double the root already found for a trial divisor, and see how many times it is contained in the dividend, omitting the last figure, and... | |
 | Algebra - 1888 - 492 pages
...root will be the cube root of the greatest cube contained in the left-hand period. Subtract this cube from the left-hand period, and to the remainder annex the next period to form a dividend. III. For a trial divisor take three times the square of the root figure, regarded... | |
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