Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend, exclusive of the righthand... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| William Frothingham Bradbury - Algebra - 1877 - 280 pages
...Find the greatest cube in the left-hand period, and place its root at the right. Subtract this cube **from the left-hand period, and to the remainder annex the next period for a dividend.** Square the root figure, annex two ciphers, and multiply this result by three for a TRIAL DIVISO» ;... | |
| James E. Ryan - Arithmetic - 1877 - 212 pages
...Find the greatest cube in the left-hand period, and write its root as a quotient. SuUract the cube **from the left-hand period, and to the remainder annex the next period for a dividend.** Consider the root figure already found as tens, and take three times its square for a TRIAL DIVISOR,... | |
| William James Milne - Arithmetic - 1877 - 402 pages
...root. Square this root and subtract the result from the left-hand period, and annex to the remainder **the next period for a dividend. Double the root already found for a** trial divisor, and by it divide the dividend, disregarding the right-hand figure. The quotient or quotient... | |
| William Guy Peck - Arithmetic - 1877 - 428 pages
...9 ; we therefore write 9 for the first figure of the root, subtract its square, 81, from the first **period, and to the remainder annex the next period for a dividend.** We then double 9 for a trial divisor, and find how many times it is contained in the dividend, exclusive... | |
| Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...product falls under the first left-hand period of the given number. Subtract this product from this first **left-hand period, and to the remainder annex the next period for a** new dividend. Add the figure of the root just found to the amount in the first column, multiply the... | |
| William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...greatest cube in the left-hand period, write its root at the right of the given number, subtract the cube **from the left-hand period, and to the remainder annex the next period for a dividend.** 3. Square the root figure, annex two ciphers, and multiply this result by three for a trial divisor... | |
| Edward Olney - Arithmetic - 1879 - 176 pages
...4th power in the left-hand period as the first figure in the root. Subtract this highest 4th power **from the left-hand period, and to the remainder annex the next period,** forming a dividend. 3. Take 4 times the 3d power of the part of the root already found (regarded as... | |
| Robert Potts - 1879 - 676 pages
...this number will be the first figure of the root. 3. Subtract the cube of this number from the last **period, and to the remainder annex the next period for a dividend.** 4. Divide this number (omitting the last two figures) by three times the square of the first figure... | |
| Robert Potts - Algebra - 1879 - 668 pages
...this number will be the first figure of the root. 3. Subtract the cube of this number from the last **period, and to the remainder annex the next period for a dividend.** 4. Divide this number (omitting the last two figures) by three times the square of the first figure... | |
| Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...product falls under the first left-hand period of the given number. Subtract this product from this first **left-hand period, and to the remainder annex the next period for a** new dividend. Add the figure of the root just found to the amount in the first column, multiply the... | |
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