 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | John Fair Stoddard - Arithmetic - 1852 - 320 pages
...divisor, 10 form the TRUE DIVISOR. Multiply the true divisor by the figure of the root last obtained ; subtract the product from the dividend, and to the remainder annex the next period for 0, NEW DIVIDEND. To the last divisor, add the last figure of the root (200+30) x4 43 200x30 To3 X o... | |
 | Benjamin Greenleaf - Algebra - 1852 - 348 pages
...divisor''s place, and the divisor will be completed. Multiply the complete divisor by the last term of the root; subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. EXAMPLES. 1. Find the cube root of a 3 +3a2J-|-3a6... | |
 | Chambers W. and R., ltd - 1854 - 152 pages
...and 36 are then added together, forming the complete divisor, 0436. EXTRACTION OF THE CUBE ROOT. 4. Multiply the complete divisor by the last figure of...; subtract the product from the dividend ; and to any remainder, annex the next period of thrce figures, to form a new dividend. 5. Form a new DivisoRas... | |
 | James Gray - Arithmetic - 1854 - 120 pages
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in the root : subtract the product from the dividend, and to the remainder bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
 | Benjamin Peirce - Algebra - 1855 - 308 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...tivo figures of the root, and the square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole... | |
 | George Roberts Perkins - Arithmetic - 1855 - 388 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the remainder annex the next period, fur a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of tlte root ; the sum, with a... | |
 | John Radford Young - 1855 - 218 pages
...will thus have the complete divisor. 4. Multiply the complete divisor by the last found root-term, subtract the product from the dividend, and to the remainder annex the two next terms of the polynomial ; you will thus have a second dividend. 5. Proceed now exactly as... | |
 | Francis Walkingame - 1855 - 186 pages
...at least, as the divisor. The first quotient figure being thus obtained, multiply the divisor by it, subtract the product from the dividend, and to the remainder annex the following figure of the dividend ; and proceed with the operation till all the figures are brought... | |
 | Elias Loomis - Algebra - 1856 - 280 pages
...figure ; annex the result both to the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring doivn the next period for a new dividend. If the product should be greater than the dividend,... | |
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