Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| John Fair Stoddard - Arithmetic - 1852 - 324 pages
...divisor, 10 form the TRUE DIVISOR. Multiply the true divisor by the figure of the root last obtained ; **subtract the product from the dividend, and to the remainder annex the next period for** 0, NEW DIVIDEND. To the last divisor, add the last figure of the root (200+30) x4 43 200x30 To3 X o... | |
| Benjamin Greenleaf - Algebra - 1852 - 352 pages
...divisor''s place, and the divisor will be completed. Multiply the complete divisor by the last term **of the root; subtract the product from the dividend, and to the remainder** connect the three next terms, and proceed as before. EXAMPLES. 1. Find the cube root of a 3 +3a2J-|-3a6... | |
| Chambers W. and R., ltd - 1854 - 148 pages
...and 36 are then added together, forming the complete divisor, 0436. EXTRACTION OF THE CUBE ROOT. 4. **Multiply the complete divisor by the last figure of...; subtract the product from the dividend ; and to** any remainder, annex the next period of thrce figures, to form a new dividend. 5. Form a new DivisoRas... | |
| James Gray - Arithmetic - 1854 - 120 pages
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in **the root : subtract the product from the dividend, and to the remainder** bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
| Benjamin Osgood Peirce - Algebra - 1855 - 308 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, **by the last figure of the root, subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
| Elias Loomis - Algebra - 1855 - 352 pages
...tivo figures of the root, and the square of the second figure. 5. Multiply the divisor thus increased **by the last figure of the root ; subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. 6. Take three hundred times the square of the whole... | |
| George Roberts Perkins - Arithmetic - 1855 - 382 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and **subtract the product from the dividend, and to the remainder annex the next period,** fur a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of tlte root ; the sum, with a... | |
| John Radford Young - 1855 - 214 pages
...will thus have the complete divisor. 4. Multiply the complete divisor by the last found root-term, **subtract the product from the dividend, and to the remainder annex the** two next terms of the polynomial ; you will thus have a second dividend. 5. Proceed now exactly as... | |
| Francis Walkingame - 1855 - 184 pages
...at least, as the divisor. The first quotient figure being thus obtained, multiply the divisor by it, **subtract the product from the dividend, and to the remainder annex the** following figure of the dividend ; and proceed with the operation till all the figures are brought... | |
| Elias Loomis - Algebra - 1856 - 280 pages
...figure ; annex the result both to the root and the divisor. 4. Multiply the divisor, thus increased, **by the last figure of the root ; subtract the product from the dividend, and to the remainder** bring doivn the next period for a new dividend. If the product should be greater than the dividend,... | |
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