Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Edward Gideon - 1902 - 276 pages
...in the dividend, and place the result in the root, and also at the right of the trial divisor. IV. **Multiply the complete divisor by the last figure of...the root; subtract the product from the dividend,** and'to the remainder annex the next period for a new dividend. V. Proceed in the same manner with all... | |
| William James Milne - Algebra - 1902 - 620 pages
...trial divinar the figure last found, multiply this complete divisor b>/ the figure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all tJte periods have been used. TJie result icill... | |
| William Estabrook Chancellor - Arithmetic - 1902 - 178 pages
...of the root x 30 and the square of the last figure of the root. multiply the divisor thus completed **by the last figure of the root; subtract the product from the dividend, and** tu the remainder briny down the next period for a new dividend. Proceed thus till the irork is completed.... | |
| Joseph Ray - Arithmetic - 1903 - 364 pages
...right-hand figure ; place the quotient in the root, and also on the right of the trial divisor. 4. **Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder** bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor,... | |
| Jacob Henry Minick, Clement Carrington Gaines - Business mathematics - 1904 - 412 pages
...divisor for a complete divisor the second figure of the root ; multiply this divisor by the second **figure of the root, subtract the product from the dividend, and to** tJie remainder annex the next period for the next dividend. Double the root now found for a second... | |
| William James Milne - Arithmetic - 1906 - 364 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. 1. When the number is not a perfect square, annex periods of decimal ciphers and... | |
| William James Milne - Arithmetic - 1906 - 364 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
| Orville Marcellus Powers - Business mathematics - 1906 - 384 pages
...second figure of the root. c. Annex the last figure of the root to the trial divisor for the complete **divisor. Multiply the complete divisor by the last figure of the root,** write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
| Charles Wilbur Leigh - 1906 - 72 pages
...Square the last figure of the root, and add both products to the trial divisor. The sum is the complete: **divisor. Multiply the complete divisor by the last figure of the root,** and subtract the product from the dividend. Bring down the next period to form, with the remainder,... | |
| Orville Marcellus Powers - Business mathematics - 1906 - 384 pages
...second figure of the root. e. Annex the last figure of the root to the trial divisor for the complete **divisor. Multiply the complete divisor by the last figure of the root,** write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
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