 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | Edward Gideon - 1902 - 276 pages
...in the dividend, and place the result in the root, and also at the right of the trial divisor. IV. Multiply the complete divisor by the last figure of...the root; subtract the product from the dividend, and'to the remainder annex the next period for a new dividend. V. Proceed in the same manner with all... | |
 | William James Milne - Algebra - 1902 - 620 pages
...trial divinar the figure last found, multiply this complete divisor b>/ the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all tJte periods have been used. TJie result icill... | |
 | William Estabrook Chancellor - Arithmetic - 1902 - 178 pages
...of the root x 30 and the square of the last figure of the root. multiply the divisor thus completed by the last figure of the root; subtract the product from the dividend, and tu the remainder briny down the next period for a new dividend. Proceed thus till the irork is completed.... | |
 | Joseph Ray - Arithmetic - 1903 - 364 pages
...right-hand figure ; place the quotient in the root, and also on the right of the trial divisor. 4. Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor,... | |
 | Jacob Henry Minick, Clement Carrington Gaines - Business mathematics - 1904 - 412 pages
...divisor for a complete divisor the second figure of the root ; multiply this divisor by the second figure of the root, subtract the product from the dividend, and to tJie remainder annex the next period for the next dividend. Double the root now found for a second... | |
 | William James Milne - Arithmetic - 1906 - 364 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 1. When the number is not a perfect square, annex periods of decimal ciphers and... | |
 | William James Milne - Arithmetic - 1906 - 364 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | Orville Marcellus Powers - Business mathematics - 1906 - 384 pages
...second figure of the root. c. Annex the last figure of the root to the trial divisor for the complete divisor. Multiply the complete divisor by the last figure of the root, write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
 | Charles Wilbur Leigh - 1906 - 72 pages
...Square the last figure of the root, and add both products to the trial divisor. The sum is the complete: divisor. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend. Bring down the next period to form, with the remainder,... | |
 | Orville Marcellus Powers - Business mathematics - 1906 - 384 pages
...second figure of the root. e. Annex the last figure of the root to the trial divisor for the complete divisor. Multiply the complete divisor by the last figure of the root, write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
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