Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| George Albert Wentworth - Arithmetic - 1889 - 434 pages
...second part. This sum will be the complete divisor. Multiply the complete divisor by the second part **of the root, subtract the product from the dividend, and to the remainder annex the next** group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
| William Frothingham Bradbury - Algebra - 1889 - 444 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root ßgure, **subtract the product from the dividend, and to the remainder annex the next period for a** dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
| William James Milne - Arithmetic - 1892 - 440 pages
...complete divisor the Jigure last found, multiply this divisor by the last Jigure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
| George Edward Atwood - Arithmetic - 1894 - 396 pages
...quotient to the root and also to the divisor. Multiply the completed divisor by the last figure in **the root, subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in the same manner until all the periods have been used. NOTE 1. If the... | |
| William James Milne - Algebra - 1894 - 214 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
| William James Milne - Algebra - 1894 - 216 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
| George Albert Wentworth - Arithmetic - 1894 - 370 pages
...be the complete divisor. Multiply the complete divisor by the second part of the root, sub- . tract **the product from the dividend, and to the remainder annex the next** group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
| George Albert Wentworth - Arithmetic - 1896 - 526 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this **complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next** group for a new dividend. Proceed in this .manner until all the groups have been thus annexed. The... | |
| Emerson Elbridge White - Algebra - 1896 - 422 pages
...and the square of the second; and then multiply the complete divisor thus formed by the second tenn **of the root, subtract the product from the dividend, and to the** difference annex the next period as another dividend. Proceed in like manner until all the figures... | |
| George Albert Wentworth - Arithmetic - 1897 - 476 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this **complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next** group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
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