Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Edward Olney - Arithmetic - 1879 - 404 pages
...the tria' divisor, thus forming the True Dijisor. Multiply the true divisor by the last root figure, **subtract the product from the dividend, and to the remainder annex the next period.** IV. Repeat the process described in the last paragraph till the work is complete. When any trial divisor... | |
| Shelton Palmer Sanford - Algebra - 1879 - 344 pages
...trial divisor to form• the complete divisor. III. Multiply the complete divisor by the second term **of the root, subtract the product from the dividend, and to the remainder** bring down as many terms as may be necessary for a new dividend. IV. Double the terms of the root already... | |
| George E. Seymour - Arithmetic - 1880 - 328 pages
...annexing the square of the last figure of the root. VII. Multiply the complete divisor thus found, **by the last figure of the root, subtract the product from the dividend, and** bring down the next period. VIII. Square the root noio found and multiply by three for a trial divisor.... | |
| William James Milne - Algebra - 1881 - 360 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
| A. Melrose - 1881 - 310 pages
...root and on the right of the divisor ; then multiply the divisor thus completed by this figure, and **subtract the product from the dividend, and to the remainder annex the** neit period for a new dividend. To the completed divisor add the figure last placed in the root, for... | |
| Arithmetic - 1882 - 392 pages
...the trial divisor, thus forming the complete divisor. 2. Multiply the complete divisor by the second **figure of the root; subtract the product from the...dividend; and to the remainder annex the next period for a** dividend. IV. To find the succeeding figures of the root:— Proceed with t/ie second, and with each... | |
| James Gray - Arithmetic - 1883 - 152 pages
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in **the root : subtract the product from the dividend, and to the remainder** bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
| James William Nicholson - Arithmetic - 1885 - 348 pages
...it to the trial divisor, to form the complete divisor. Multiply the complete divisor by the second **figure of the root ; subtract the product from the...dividend, and to the remainder annex the next period for a** dividend. Proceed with the second, and with each succeeding dividend, in the same manner as with the... | |
| George Albert Wentworth - Arithmetic - 1889 - 674 pages
...root. To this partial divisor add the second part of the root for a complete divisor. Multiply this **complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next** group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
| James William Nicholson - Arithmetic - 1889 - 408 pages
...to the trial divisor, to form the complete divisor. IV. Afultiply the complete divisor by the second **figure of the root; subtract the product from the...dividend, and to the remainder annex the next period for a** dividend. V. Proceed with the second, and with each succeeding dividend, in the same manner as with... | |
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