Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| William James Milne - Arithmetic - 1907 - 616 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. 22 245 l'.56'25 |1.25 1 56 44 1225 1225 1. When the number is not a perfect square,... | |
| William James Milne - Algebra - 1908 - 476 pages
...divisor the figure last found, multiply this complete divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
| George E. Mercer - Arithmetic - 1909 - 312 pages
...Add this figure of the root to the trial divisor to obtain the complete divisor. (7) Multiply this **complete divisor by the last figure of the root, subtract the product from the dividend, and** annex the next group to the remainder. (8) Repeat (4) to (7) until all the groups have been used. If... | |
| William James Milne - 1911 - 360 pages
...divisor the figure last found, multiply this complete divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
| Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...first considered as tens, also the square of the second figure, and the result will be the complete **divisor. Multiply the complete divisor by the last figure of the root,** -and subtract the product from the dividend. If there are more periods to be brought down, proceed... | |
| Glenn Moody Hobbs - 1912 - 100 pages
...the trial divisor, and multiply the completed divisor by the last figure in the root. Subtract this **product from the dividend, and to the remainder annex the next period for** the new dividend. Continue the operation until all the periods are used. (d) To place the decimal point... | |
| James A. Lyons - Business mathematics - 1912 - 392 pages
...second figure of the root. e. Annex the last figure of the root to the trial divisor for the complete **divisor. Multiply the complete divisor by the last figure of the root,** write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
| George E. Mercer, Mabel Bonsall - Arithmetic - 1914 - 324 pages
...Add this figure of the root to the trial divisor to obtain the complete divisor. (7) Multiply this **complete divisor by the last figure of the root, subtract the product from the dividend, and** annex the next group to the remainder. (8) Repeat (4) to (7) until all the groups have been used. If... | |
| William James Milne - Arithmetic - 1914 - 524 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. 22 1' 1 .56' 25 |1.25 245 56 44 12 12 25 25 1. When the number is not a perfect... | |
| Theodore Lucas, Frank Duncan Graham, Nehemiah Hawkins - Marine engineering - 1918 - 940 pages
...figure of the root. Annex this quotient to the right of tit* J''e; trial divisor to form the complete **divisor. Multiply the complete • ^ divisor by the last figure of the root,** and subtract the product *'*•'• from the dividend. To t/te remainder annex the next period, and... | |
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