 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | William James Milne - Arithmetic - 1907 - 616 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 22 245 l'.56'25 |1.25 1 56 44 1225 1225 1. When the number is not a perfect square,... | |
 | William James Milne - Algebra - 1908 - 476 pages
...divisor the figure last found, multiply this complete divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | George E. Mercer - Arithmetic - 1909 - 312 pages
...Add this figure of the root to the trial divisor to obtain the complete divisor. (7) Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and annex the next group to the remainder. (8) Repeat (4) to (7) until all the groups have been used. If... | |
 | William James Milne - 1911 - 360 pages
...divisor the figure last found, multiply this complete divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...first considered as tens, also the square of the second figure, and the result will be the complete divisor. Multiply the complete divisor by the last figure of the root, -and subtract the product from the dividend. If there are more periods to be brought down, proceed... | |
 | Glenn Moody Hobbs - 1912 - 100 pages
...the trial divisor, and multiply the completed divisor by the last figure in the root. Subtract this product from the dividend, and to the remainder annex the next period for the new dividend. Continue the operation until all the periods are used. (d) To place the decimal point... | |
 | James A. Lyons - Business mathematics - 1912 - 392 pages
...second figure of the root. e. Annex the last figure of the root to the trial divisor for the complete divisor. Multiply the complete divisor by the last figure of the root, write this under the dividend, subtract, bring down the next period if any, and continue as before.... | |
 | George E. Mercer, Mabel Bonsall - Arithmetic - 1914 - 324 pages
...Add this figure of the root to the trial divisor to obtain the complete divisor. (7) Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and annex the next group to the remainder. (8) Repeat (4) to (7) until all the groups have been used. If... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...complete divisor the figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 22 1' 1 .56' 25 |1.25 245 56 44 12 12 25 25 1. When the number is not a perfect... | |
 | Theodore Lucas, Frank Duncan Graham, Nehemiah Hawkins - Marine engineering - 1918 - 940 pages
...figure of the root. Annex this quotient to the right of tit* J''e; trial divisor to form the complete divisor. Multiply the complete • ^ divisor by the last figure of the root, and subtract the product *'*•'• from the dividend. To t/te remainder annex the next period, and... | |
| |
