Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...right of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second **figure of the root, subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE,... | |
| Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...correction to (he trial divisor ; add the correction, and the result will be the complete divisor. V. **Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder** bring down another period for a new dividend. VI. Add together the square of the last figure of the... | |
| William Guy Peck - Algebra - 1875 - 348 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial **figure of the root, subtract the product from the dividend, and to the remainder annex the** -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
| Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in **the root, subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
| Joseph Ray - Arithmetic - 1877 - 404 pages
...square the last figure; add the products to the trial divisor ; the sum is the complete divisor. 5. **Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder** bring floirn the next period for a new dividend. 6. Find a new trial divisor as before, and continue... | |
| William Frothingham Bradbury - Algebra - 1877 - 280 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, **subtract the product from the dividend, and to the remainder annex the next period for a** dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
| William Guy Peck - Arithmetic - 1877 - 428 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial **-figure of the root, subtract the product from the dividend, and to the remainder annex the** following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
| William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, **subtract the product from the dividend, and to the remainder annex the next period for** the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
| Albert Newton Raub - Arithmetic - 1877 - 348 pages
...5. Put this figure of the root in place of the cipher, and then multiply the entire divisor by this **last figure of the root; subtract the product from the dividend, and to the** difference annex the next period for a new dividend. 6. Double the root already found, with a cipher... | |
| Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...place the result in the root and at the right of the divisor. IV. Multiply the divisor thus completed **by the last figure of the root ; subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. V. Double the right-hand figure of the last complete... | |
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