 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...right of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE,... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...correction to (he trial divisor ; add the correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Joseph Ray - Arithmetic - 1877 - 404 pages
...square the last figure; add the products to the trial divisor ; the sum is the complete divisor. 5. Multiply the complete divisor by the last figure of...the product from the dividend, and to the remainder bring floirn the next period for a new dividend. 6. Find a new trial divisor as before, and continue... | |
 | William Frothingham Bradbury - Algebra - 1877 - 280 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
 | William Guy Peck - Arithmetic - 1877 - 428 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial -figure of the root, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
 | Albert Newton Raub - Arithmetic - 1877 - 348 pages
...5. Put this figure of the root in place of the cipher, and then multiply the entire divisor by this last figure of the root; subtract the product from the dividend, and to the difference annex the next period for a new dividend. 6. Double the root already found, with a cipher... | |
 | Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...place the result in the root and at the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the right-hand figure of the last complete... | |
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