 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | George Albert Wentworth - Arithmetic - 1889 - 434 pages
...second part. This sum will be the complete divisor. Multiply the complete divisor by the second part of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 444 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root ßgure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
 | William James Milne - Arithmetic - 1892 - 440 pages
...complete divisor the Jigure last found, multiply this divisor by the last Jigure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
 | George Edward Atwood - Arithmetic - 1894 - 396 pages
...quotient to the root and also to the divisor. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in the same manner until all the periods have been used. NOTE 1. If the... | |
 | William James Milne - Algebra - 1894 - 214 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | William James Milne - Algebra - 1894 - 216 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | George Albert Wentworth - Arithmetic - 1894 - 374 pages
...be the complete divisor. Multiply the complete divisor by the second part of the root, sub- . tract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
 | George Albert Wentworth - Arithmetic - 1896 - 490 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this .manner until all the groups have been thus annexed. The... | |
 | Emerson Elbridge White - Algebra - 1896 - 418 pages
...and the square of the second; and then multiply the complete divisor thus formed by the second tenn of the root, subtract the product from the dividend, and to the difference annex the next period as another dividend. Proceed in like manner until all the figures... | |
 | George Albert Wentworth - Arithmetic - 1897 - 480 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
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