 | Benjamin Greenleaf - Geometry - 1868 - 340 pages
...Draw BE and AF perpendicular AB to AB, and produce CD to F. Then the parallelogram ABCD is equivalent to the rectangle ABEF, which has the same base, AB, and the same altitude, BE (Prop. I. Cor.). But the rectangle ABEF is measured by AB X BE (Prop. IV. Sch.) ; therefore AB X... | |
 | William Chauvenet - Geometry - 1871 - 380 pages
...is measured by the product of the numerical measures of the lines. PROPOSITION IV.— THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and... | |
 | Elias Loomis - Geometry - 1871 - 302 pages
...base, and the oth«r the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its altitude, and AB its base ; then is its surface... | |
 | William Frothingham Bradbury - Geometry - 1872 - 124 pages
...be neglected. 91 Corollary. The area of a square is the square of one of its sides. THEOREM III. 101 The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ _ F 0 lelogram ABCD ; then the area of / . \7 At A draw the... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...product is equal to the area of a rectangle constructed with the lines as sides. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and BE its altitude : then will the area of ABCD be equal... | |
 | William Frothingham Bradbury - Geometry - 1872 - 262 pages
...be neglected. 9. CoroUary. The area of a square is the square of one of its sides. THEOREM III. 10, The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ FC lelogram A BCD; then the area of \l '. [~7 ABCD — ADXDF.... | |
 | William Chauvenet - Mathematics - 1872 - 382 pages
...lines is measured by the product of the numerical measures of the lines. PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and... | |
 | Benjamin Greenleaf - Geometry - 1873 - 202 pages
...Draw BE and AF perpendicular to AB AB, and produce CD to F. Then the parallelogram ABCD is equivalent to the rectangle ABEF, which has the same base, AB, and the same altitude, BE (Theo. I. Cor.). But the rectangle ABEF is measured by ABX BE (Theo. IV. Sch.) ; therefore ABXBE... | |
 | Henry William Jeans - 1873 - 292 pages
...57°.39577— 57°-29577 — 5729577" whence BAC=53° 38' 30", and a;=100xtan. BAC=407-5. PROB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle =£ area of a parallelogram with same base and altitude,... | |
 | Henry W. Jeans - 1873 - 272 pages
...4x57°-29577 57°-29577 5729577 whence BAC=53° 38' 30", and *=100 xtan. BAC=407'5. PEOB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle = J area of a parallelogram with same base and altitude,... | |
| |
The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
