 | William Frothingham Bradbury - Geometry - 1880 - 260 pages
...will evidently contain 5X4, or 20, of these squares; that is, its area = 5 X 4 = 20. THEOREM XVI. 43. The area of a parallelogram is equal to the product of its base and altitude. lelogram ABCD ; then the area of j 7 ~7 Let DF be the altitude of the paral- EBFC / At A draw the perpendicular... | |
 | George Anthony Hill - Geometry - 1880 - 332 pages
...positions shown in the figure. Corollaries. — I. By combining this theorem with § 128, we see that the area of a parallelogram is equal to the product of its base by its altitude. 2. All parallelograms having equal bases and equal altitudes are equivalent.... | |
 | George Albert Wentworth - Geometry, Modern - 1881 - 266 pages
...; and the area of the figure equals 7X4. ! : i • Î : ! 1 ._ ! | ! PROPOSITION IV. THEOREM. 321. The area of a parallelogram is equal to the product of its base and altitude, BE С FB СE F D AD Let AE FD be a parallelogram, AD its base, and С D its altitude. We are to prove... | |
 | Education - 1890 - 384 pages
...x, equidistant from two given points, and also equidistant from two given parallel lines. 8. Prove: The area of a parallelogram is equal to the product of its base and altitude. 5). The base of a triangle is UK) varas .the altitude is 50 varas. What is its area. 10. The diameter... | |
 | Edward Olney - Geometry - 1883 - 344 pages
...of its sides, as in this case the base and altitude are equal. 346. COROLLARY 2.—The area of any parallelogram is equal to the product of its base and altitude; for any parallelogram is equivalent to a rectangle of the same base and altitude (332). 347. COROLLARY... | |
 | F. B. Stevens - Examinations - 1884 - 202 pages
...a triangle divides the opposite side into segments whi^h are proportional to the adjacent sides. 3. The area of a parallelogram is equal to the product of its base and altitude. 4. How do you find the area of a trapezoid ? The areas of similar polygons are to each other in what... | |
 | Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...product is equal to the area of a rectangle constructed with the lines as sidea PROPOSITION V. THEOREM. The area of a parallelogram, is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and BE its altitude : then the area of ABCD is equal to AB... | |
 | Webster Wells - Geometry - 1886 - 392 pages
...square inches, and its base is 2 yards, what is its perimeter in feet? PROPOSITION IV. THEOREM. 324. The area of a parallelogram is equal to the product of its base and altitude. EBFC A b Let ABCD be a parallelogram having its altitude DF equal to a and its base AD equal to b.... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...PROPOSITION IV. The area of a rectangle is equal to the product of its base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and altitude. PROPOSITION VI. The area of a triangle is equal to half the product of its base and altitude. Corollary... | |
 | George Albert Wentworth - Geometry - 1888 - 272 pages
...the figure equals 7x4 units of surface. PLANE GEOMETRY. — BOOK IV. PROPOSITION IV. THEOREM. 365. The area of a parallelogram is equal to the product of its base and altitude. BECF A b DA 6 Z> Let AEFD be a parallelogram, AD its base, and CD its altitude. To prove the area of... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
