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" The area of a parallelogram is equal to the product of its base and its height: A = bx h. "
The New Practical Builder and Workman's Companion, Containing a Full Display ... - Page 51
by Peter Nicholson - 1823 - 596 pages
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Plane and Solid Geometry

James Howard Gore - Geometry - 1898 - 232 pages
...linear units in its base by the number of linear units in its altitude. PROPOSITION IV. THEOREM. 251. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram. To prove that the area of £-2 ABCD = ABx AF. \ / Erect the perpendiculars...
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The Essentials of Geometry (plane)

Webster Wells - Geometry - 1898 - 250 pages
...the product of 6 and 5, the numbers which express the lengths of the sides. PROP. IV. THKOREM. 309. The area of a parallelogram is equal to the product of its base and altitude. EB FC A h D Given O ABCD, with its altitude DF = a, and its base AD=b. To Prove area ABCD = a x b....
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An Elementary Course in Analytic Geometry

John Henry Tanner, Joseph Allen - Geometry, Analytic - 1898 - 458 pages
...about the ellipse ; its sides are parallel to, and equal in length to, the conjugate diameters. Since the area of a parallelogram is equal to the product of its adjacent sides and the sine of the included angle, therefore the area of this circumscribed parallelogram...
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The Essentials of Geometry

Webster Wells - Geometry - 1899 - 424 pages
...the product of 6 and 5, the numbers which express the lengths of the sides. PROP. IV. THEOREM. 309. The area of a parallelogram is equal to the product of its base and altitude. BFC A b D Given O ABCD, with its altitude DF=a, and its base To Prove area ABCD = ax b. Proof. Draw...
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The Essentials of Geometry

Webster Wells - Geometry - 1899 - 450 pages
...the product of 6 and 5, the numbers which express the lengths of the sides. PROP. IV. THEOREM. 309. The area of a parallelogram is equal to the product of its base and altitude. EBFC AI) D Given O ABCD, with its altitude DF= a, and its base AD = b. To Prove area ABCD = ax b. Proof....
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The Elements of Plane Geometry

Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...unit of surface ; that is, the area is equal to 6 x 4 units of surface. Proposition 165. Theorem. 201. The area of a parallelogram is equal to the product of its base and altitude. A a Hypothesis. ABCD is a O whose base and altitude are AB and BE respectively. Conclusion. Area of...
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Observational Geometry

William Taylor Campbell - Geometry - 1899 - 276 pages
...feet wide instead of 27 feet. How much additional area does it contain f 2. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. The base is any one of the sides. The altitude is the perpendicular distance between the base and the...
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Syllabus of Propositions in Geometry: Intended for Use in Preparing Students ...

Harvard University - Geometry - 1899 - 39 pages
...Corollary. The area of a rectangle is equal to the product of its base and its altitude. THEOREM IV. The area of a parallelogram is equal to the product of its base and its altitude. THEOREM V. The area of a triangle is equal to half the product of its base and its altitude....
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Solid Geometry, Volumes 6-9

George Albert Wentworth - Geometry, Solid - 1899 - 246 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403....
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Plane and Solid Geometry

George Albert Wentworth - Geometry - 1899 - 498 pages
...by dividing the figure into squares, each T~ BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE OF B GE A b DAI) D Let AEFD be a parallelogram, b its base, and a its altitude....
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