 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...square on a single one ; on a triple line it is nine times as great, &c. E PROPOSITION V. THEOEEM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram, and BE its altitude : then will its area be equal to ABxBE. Draw Af]... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...the square on a single one ; on a triple line it is nine times as great, &c. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram, and BE its altitude: then will its area be equal to AB x BE. Draw BE... | |
 | Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...is an equilateral parallelogram or rhojnbus. The diagonals of a rectangle are equal to each other. The area of a parallelogram is equal to the product of its base by its altitude. Any two parallelograms having the same or equal bases are to each other as their... | |
 | Peter Nicholson - Cabinetwork - 1856 - 518 pages
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 43. 111. The area of a parallelogram is equal to the product...which has the same base AB, and the same altitude (102), and this last is measured by ABxBE, or by ABx AF; that is, the product of the base of the parallelogram... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...as the square on a single one ; on a triple line it is nine times as great, PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its boat and altitude. Let ABCD be any parallelogram, and BE its altitude: then will its area be equal... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its -pn EC altitude, and AB its base ; then is... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...and AF perpendicular to AB, and produce С D to F. AB Then the parallelogram А В С D is equivalent to the rectangle ABEF, which has the same base, AB, and the same altitude, BE (Prop. I. Cor.) . But the rectangle ABEF is measured by ABX BE (Prop. IV. Sch.) ; therefore AB X... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...Draw BE and AF perpendicular AB to AB, and produce CD to F. Then the parallelogram ABCD is equivalent to the rectangle ABEF, which has the same base, AB, and the same altitude, BE (Prop. I. Cor.). But the rectangle ABEF is measured by ABX BE (Prop. IV. Sch.) ; therefore AB X... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...Draw BE and AF perpendicular AB to AB, and produce CD to F. Then the parallelogram ABCD is equivalent to the rectangle ABEF, which has the same base, AB, and the same altitude, BE (Prop. I. Cor.). But the rectangle ABE F is measured by AB X BE (Prop. IV. Sch.) ; therefore AB... | |
 | Edward Brooks - Geometry - 1868 - 284 pages
...cancelling the equal factor in the second couplet of Cor. 1, we have, ABCD : EFGH:: AB : EF. THEOREM II. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and EB its altitude; then will its area be equal to For,... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
