 | George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETKY". PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE CF CE A b ~ DA J> ' D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
 | Education - 1899 - 824 pages
...assumed without proof. Among the other error» in proving the second part it wa.s taken for true that the area of a parallelogram is equal to the product of its two adjacent sides. Questions 7. 8, and 9 were correctly demonstrated by nearly all (a considerable... | |
 | William James Milne - Geometry, Modern - 1899 - 258 pages
...=0= A AD F + A BED ; that is, ABCD =0= ABEF. Therefore, etc. QED MILNE'S GEOM. — 12 332. Cor. I. The area of a parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and an equal altitude. (Art.... | |
 | Metal-work - 1901 - 548 pages
...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two opposite sides AB... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...303. (6) The area of any rectangle is equal to the product of its base and its altitude. § 304. (7) The area of a parallelogram is equal to the product of its base and its altitude. § 305. (8) The area of a square is equal to the square of any one of its sides. § 307.... | |
 | Arthur Schultze - 1901 - 392 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h.... | |
 | Arthur Schultze - 1901 - 260 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...rectangle is 360 square inches, and its base ia 4 yds. Find the altitude. PROPOSITION IV. THEOREM 341. TJie area of a parallelogram is equal to the product of its base and its altitude. Hyp. ABCD is a parallelogram, having the base AB — b, and the altitude BE = h. To prove... | |
 | Arthur Schultze - 1901 - 260 pages
...rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. TTie area of a parallelogram is equal to the product of its base and its altitude. A Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To frnn.e... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
