Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. The Common School Arithmetic ... - Page 308by James Stewart Eaton - 1868 - 312 pagesFull view - About this book
| James Bates Thomson - Arithmetic - 1848 - 434 pages
...common difference ? GO5. To find the number of terms, when the extremes and common difference are given. Divide the difference of the extremes by the common difference, and the quotient increased by 1 will be the number of terms. OBS. The truth, of this principle is manifest from the manner in which... | |
| Pliny Earle Chase - Arithmetic - 1848 - 244 pages
...5, gives 7, which must be equal to the number of terms less 1. Therefore the number of terms is 8. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 13. What is the sum of the series 2, 4, 6, 8, &c., to 1000? 14. What is the... | |
| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...140.) CASE IV. The first term, last term and common difference given, to Jind the number of terms. RULE. Divide the difference of the extremes by the...common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1 . A man bought cloth in arithmetical progression, giving 5... | |
| Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...of the extremes, and the product divided by 2, the quotient will be the sum of the series. Hence the RULE. — Divide the difference of the extremes by the common difference, and add 1 to the quotient ; multiply this sum by the sum of the extremes, and half the product is the sum... | |
| J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...29-3=26 ; and 26-M3=2. Ans. Gicen the Common Difference and the Extremes, to find the Number of Terms. Rule. — Divide the difference of the extremes by the common difference, and to the quotient add one. Example. — The first term of an arithmetical progression is 11, the last... | |
| George Roberts Perkins - Arithmetic - 1849 - 344 pages
...the first term, the last term, and the common difference, to find the number of terms, we have this RULE. Divide the difference of the extremes by the common difference, and to the quotient add one. EXAMPLES. 1. The first term of an arithmetical progression is 5, the last... | |
| Charles Guilford Burnham - 1850 - 350 pages
...When the first and last terms, and the common difference are given, to find the number of terms — RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the last term... | |
| Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...12. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increasedby 1, will be the answer. 32. If the extremes be 3 and 45, and the common difference 6, what... | |
| George Roberts Perkins - Arithmetic - 1850 - 356 pages
...the first term, the last term, and the common difference, to find the number of terms, we have this RULE. Divide the difference of the extremes by the common difference, and to the quotient add one. EXAMPLES. 1. The first term of an arithmetical progression is 5, the last... | |
| Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...the sum of the extremes, and the product divided by 2, the quotient would be the sum of the series. RULE. — Divide the difference of the extremes by the common difference, and add 1 to the quotient; multiply this quotient by the sum of the extremes, and half the product is the... | |
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