 Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.  The Common School Arithmetic ... - Page 308by James Stewart Eaton - 1868 - 312 pagesFull view - About this book
 | John Rose - Arithmetic - 1835 - 192 pages
...Given the extremes (the first and last terms,) and the common difference, to find the number of terms. Divide the difference of the extremes, by the common difference, and the quotient increased by 1 will be the number of terms required. 1. The extremes are 2 and 53, and the common difference 3; what... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...difference, to find the number of terms. RULE. — Divide the difference of the extremes by the cormr-on difference, and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each day by... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...debt. PROBLEM III. Given the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of the extremes by the...difference, and the quotient increased by 1 is the num ber of terms. EXAMPLES. If the extremes be 2 and 45, and 45, and the com mon difference^; what... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...— When the first and last terms, and the common difference are given, to find the number of terms : RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the last term... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by...the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each day by... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by...the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each' day by... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...first term, the last term, and the common differenet given to find the number of terms. . . ROLE. — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 2. If the first term of a series be 8. the last 108, and the common difference... | |
 | Nathan Daboll - 1839 - 220 pages
...yards. CASE IV. TAe first term, last term and common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the...common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1 . A man bought cloth in arithmetical progression, giving 5... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...miles, 2 rods. PROBLEM HI. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by one, will be the number of terms required. 9. If the extremes are 3 and 45, and the common difference... | |
 | Roswell Chamberlain Smith - 1839 - 308 pages
...Л. 12. Hence, When the Extremes and Common Difference are given, In Jim L the Number of Terms ; — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 17. If the extremes he 3 and 45, and the common difference 6, what is the number... | |
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