 Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.  The Common School Arithmetic ... - Page 308by James Stewart Eaton - 1868 - 312 pagesFull view - About this book
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 318 pages
...;,. 12. Hence, When the Extremes mid Common Difference ore given, to ßnd the Number of Terms ; — Divide the difference of the extremes by the common difference, and the quotient, increasnd by 1, will be the answer. 17. If the extremes be 3 and 45, and the common difference 6, what... | |
 | Pliny Earle Chase - Arithmetic - 1844 - 246 pages
...5, gives 7, which must be equal to the number of terms less 1. Therefore the number of terms is 8. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 13. What is the sum of the series 2, 4, 6, 8, &c., to 1000? 14. What is the... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 352 pages
...miles, 2 rods. PROBLEM III. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and Ike quotient increased by one, will be the number of terms required 9. If the extremes are 3 and 45,... | |
 | Pliny Earle Chase - 1844 - 258 pages
...5, gives 7, which must be equal to the number of terms less 1. Therefore the number of terms is 8. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 13. What is the sum of the series 2, 4, 6,8, &c., to 1000? 14. What is the sum... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...(134-2) =78 4«t. When the Common Difference and the Extremes are gieen, to find the Number of Terms. RULE.— Divide the difference of the extremes by the common difference, and add one to the quotient. EXAMPLE. — A man travelled 3 miles the first day, 5 the second, 7 the third,... | |
 | George Hutton (arithmetic master, King's coll. sch.) - 1844 - 276 pages
...difference being given, to find the number of terms in the series. RULE. Divide the difference between the extremes by the common difference, and the quotient increased by 1 will be the number of the terms. EXAMPLES FOR PRACTICE. 1. The extremes of an arithmetical progression... | |
 | Almon Ticknor - Arithmetic - 1846 - 274 pages
...will be doubled. Given the extremes and the common difference, to find the number of terms. RULE in. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms required. 5. The extremes are 3 and 39, and the common difference 2 ; what... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...CASE 3. Given the first term, the last term, and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the...the quotient increased by 1 is the number of terms required. EXAMPLES. 1. The extremes are 2 and 53, and the common difference 3 : what is the number... | |
 | James Bates Thomson - Arithmetic - 1847 - 434 pages
...common difference ? To find the number of terms, when the extremes and common difference are given. Divide the difference of the extremes ~by the common difference, and the quotient increased by 1 will be the number of terms. OBS. Tlie truth of this principle is manifest from the manner in which... | |
 | Arithmetic - 1847 - 292 pages
...the first term, the last term, and the common difference, tojind the number of terms. RULE. — 0) Divide the difference of the extremes by the common difference, and the quotient increased by one is the number of terms required. Question. — 1. The first and last terms, and common difference... | |
| |
