 Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.  The Common School Arithmetic ... - Page 308by James Stewart Eaton - 1868 - 312 pagesFull view - About this book
 | Frederick Emerson - Arithmetic - 1839 - 300 pages
...miles travelled. PROBLEM in. The extremes and common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient; the sum will be the number of terms. The difference of the extremes divided... | |
 | Calvin Tracy - Arithmetic - 1840 - 316 pages
...8+1=9, the whole number of terms, or answer required. From the above we derive the following rule : RULE. — Divide the difference of the extremes by the common difference, and add one to the quotient. 2. A man commenced a journey, and traveled the first day only 4 miles ; after... | |
 | Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...miles, 2 rods. PROBLEM IIL Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by one, will be the number of terms required. 9. If the eXtremes are 3 and 45, and the common difference... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...18. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the ainicer. 3-2. If the extremes be 3 and 45, and the common difference 6. what is the number... | |
 | Arithmetic - 1841 - 200 pages
...CASE IV. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — (') Divide the difference of the extremes...the common difference, and the quotient increased by one is the number of terms required. Question. — 1. The first and last terras, and common difference... | |
 | George Roberts Perkins - Arithmetic - 1841 - 274 pages
...the first term, the last term, and the common difference, to find the number of terms, wo have this RULE. Divide the difference of the extremes by the common difference, and to the quotient add one. Examples. 1. The first term of an arithmetical progression is 5, the last... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...12. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1 , will be the answer. 32. If the extremes be 3 and 45, and the common difference 6, what is the number... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...140.) CASE IV. The first term, last term and common difference given, to jind the number of terms. RULE. Divide the difference of the extremes by the...common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1. A man bought cloth in arithmetical progression, giving 5... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 320 pages
...31. Hence, when the extremes and common difference are given, to find the number of terms:—Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 32. If the extremes be 3 and 45, and the common difference 6, what is the number... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 306 pages
...A. 12. Hence, When the Extremes and Canmon Difference are given, to find tlie Number of Terms ; — Divide the difference of the extremes by the common difference, and the quotient, increased by l, wül be the answer. 17. If the extremos he 3 and 45, and the common difference 6, what is the number... | |
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