Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
| Nathan Daboll - Arithmetic - 1823 - 262 pages
...the U'hok debt. • .. PJRbBLEM III. Given the first term, last ternl, and common difference, to fmd **the number of terms. RULE. «* " Divide the difference of the extremes by** (he common difi'eixMiee, and the quotient increased by 1 is the number of terms. • " EXAMri.rs 1.... | |
| Nathan Daboll - Arithmetic - 1824 - 264 pages
...and 9 ! 2i. the u'holt PROBLEM III. UiveB the first term, last term, and common dSftcren«v. ti• **find the number of terms. RULE. Divide the difference of the extremes by the common** diffbrence, and the quotient increased by 1 is t!ic nunibei of terms. F.XAMT-l.KS. 1. If the extremes... | |
| Zadock Thompson - Arithmetic - 1826 - 176 pages
...difference in their ages ? Ans. 3 years. Problem III. The first term, the last term, and common difference **given, to find the number of terms. RULE.! — Divide...difference of the extremes by the common difference,** and the quotient, increased by 1, is the number of terms required. Examples. 1. The extremes are 2... | |
| B. M. Tyler - Arithmetic - 1827 - 308 pages
...first day 21 miles, and the last 70; — how many miles does he increase daily ? Ans. 7. PROBLEM IV. **To find the number of terms. • RULE. Divide the...difference of the extremes by the common difference,** and add one to the quotient. Illustration. — The greatest term is made up of the common difference... | |
| Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
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| Daniel Parker - Arithmetic - 1828 - 358 pages
...: whole distance 455 miles. PROB. III. — Given the first term, last term, and common difference, **to find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by one, is the number of terms. Examples. 1. Let the extremes be 5 and 53,... | |
| William Kinne - 1829 - 248 pages
...their ages ? Ans. 4 years. PROBLEM 111. Given the first term, the last term, and the common difference, **to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference,** and the quotient increased by 1, is the number of terms required. EXAMPLES. 1. The extremes are 3 and... | |
| Nathan Daboll - Arithmetic - 1829 - 252 pages
...difference, and 9121. the whole debt. PROBLEM HI. Given the first term, last term, and common difference, **to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference,** and the quotient increased by 1 is the number of terms. EXAMPLES. 1. If the extremes be 3 and 45, and... | |
| Nathan Daboll - Arithmetic - 1829 - 268 pages
...thewhol* debt. PROBLEM III Given the first term, last term, and common difference, to find the numbei **of terms RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by 1 is the number o» terms EXAMPLES. 1. If the extremes be 3 and 45, and... | |
| Ira Wanzer - Arithmetic - 1831 - 408 pages
...$6, Ans.— Sec Ex. 3d, Prub. II. PROBLEM IV. — The extremes and the common difference of the terms **being given, to find the number of terms. RULE.—...difference of the extremes by the common difference of the** terms, and the quotient, increased by 1, will be the answer. "„ Ex. 1. If the extremes be 4 and 18,... | |
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