Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...and 8-f2rr4, and 4+1—) 5 Ans. Hence, III. The first term, the last term, and the common difference **given to find the number of terms. RULE. — Divide...difference of the extremes by the common difference,** and the quotient, increased by 1, will be the answer. 2. If the first term of a series be 8, the last... | |
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...3=3, and 8-7-2=4, and 4+1=) 5 Ans. Hence, IIL The first term, the last term, and the common difference **given to find the number of terms. RULE. — Divide...difference of the extremes by the common difference,** and the quotient, increased by 1, will be the answer. 2. If the first term of a series be 8, the last... | |
| Nicolas Pike - Arithmetic - 1832 - 544 pages
...9-|-9+9+9+94-6+9+9 =9X8=72, and 1+2+3+4+5+6+7+8=— =36 PROBLEM III. Gil-en the extremes and the common difference, **to find the number of terms. RULE.* Divide the difference of the extremes by the common difference,** and the quotient increased by 1 will be the number ef terms required. EXAMPLES. 1st. The extremes are... | |
| Francis Walkingame - 1833 - 204 pages
...the whole distance 366 miles. Case 3. The ttvo extremes and the common difference being given, lojind **the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by unity is the number sought. (6) A person travelling into the country,... | |
| Frederick Emerson - Arithmetic - 1834 - 300 pages
...daily increase, and also the number of miles travelled. PROBLEM iII. The extremes and common difference **given, to find the number of terms. RULE. Divide the...difference of the extremes by the common difference,** and add 1 to the quotient; the sum will be the number of terms. The difference of the extremes divided... | |
| George Willson - Arithmetic - 1836 - 202 pages
...their ages ? Ans; 2 years. PROBLEM IV. — Given the first term, last term, and common difference, **to find the number of terms. RULE. — Divide the difference of the extremes by the** cormr-on difference, and the quotient increased by 1 is the number of terms. 7. A man travelling a... | |
| Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...number of books purchased. Therefore — When the first and last terms, and the common difference are **given, to find the number of terms : RULE. Divide...difference of the extremes by the common difference,** and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and... | |
| George Willson - Arithmetic - 1838 - 194 pages
...their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, **to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference,** and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles... | |
| George Willson - Arithmetic - 1838 - 194 pages
...their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, **to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference,** and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles... | |
| Frederick Emerson - Arithmetic - 1839 - 300 pages
...daily increase, and also the number of miles travelled. PROBLEM in. The extremes and common difference **given, to find the number of terms. RULE. Divide the...difference of the extremes by the common difference,** and add 1 to the quotient; the sum will be the number of terms. The difference of the extremes divided... | |
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