Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
| Nathan Daboll - 1839 - 220 pages
...140.) Ans. 22 miles 3 furlongs 100 yards. CASE IV. TAe first term, last term and common difference **given, to find the number of terms. RULE. Divide the...difference of the extremes by the common difference,** and the quotient increased by 1, will be the number of terms. EXAMPLES. 1 . A man bought cloth in arithmetical... | |
| Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...to the basket ? Ans. 288090 miles, 2 rods. PROBLEM HI. Given the extremes and the common difference, **to find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by one, will be the number of terms required. 9. If the extremes are 3 and... | |
| Arithmetic - 1841 - 200 pages
...5m. distance 366m. •«* CASE IV. Given the first term, the last term, and the common difference, **to find the number of terms. RULE. — (') Divide...difference of the extremes by the common difference,** and the quotient increased by one is the number of terms required. Question. — 1. The first and last... | |
| Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...to the basket ? Ans. 288090 miles, 2 rods. PROBLEM IIL Given the extremes and the common difference, **to find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by one, will be the number of terms required. 9. If the eXtremes are 3 and... | |
| Nathan Daboll - 1843 - 260 pages
...difference, and 912/. the u-hoU w. PROBLEM III. liivcR the first term, last term, and common difterenr.p **to find the number of terms. RULE. Divide the difference of the extremes by the common** ciifturerire, and the i|uotient increased by 1 is the nuinbei of terms. * EX AM PI. ES. I. f the extremes... | |
| Nathan Daboll - Arithmetic - 1843 - 248 pages
...difference, and9l2l. ilietchoU ieb*. PROBLEM III. Given the first term, last term, and common difference **to find the number of terms. RULE. Divide the difference of the extremes by the common** ditturutice, and the quotient increased by 1 is the numbei of terms. EXAMPI.KS. I. f the extremes be... | |
| Nathan Daboll - Arithmetic - 1843 - 254 pages
...and the number of terms 140.) CASE IV. The first term, last term and common difference given, to jind **the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by 1, will be the number of terms. EXAMPLES. 1. A man bought cloth in arithmetical... | |
| Charles Haynes Haswell - Engineering - 1844 - 298 pages
...clock strike in 12 hours ? 12X (134-2) =78 4«t. When the Common Difference and the Extremes are gieen, **to find the Number of Terms. RULE.— Divide the difference of the extremes by the common difference,** and add one to the quotient. EXAMPLE. — A man travelled 3 miles the first day, 5 the second, 7 the... | |
| William Vogdes - Arithmetic - 1847 - 324 pages
...place from Washington ? § 166. CASE 3. Given the first term, the last term, and the common difference, **to find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by 1 is the number of terms required. EXAMPLES. 1. The extremes are 2 and... | |
| J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...required the common difference. 29-3=26 ; and 26-M3=2. Ans. Gicen the Common Difference and the Extremes, **to find the Number of Terms. Rule. — Divide the...difference of the extremes by the common difference,** and to the quotient add one. Example. — The first term of an arithmetical progression is 11, the... | |
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