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" Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. "
The parallel arithmetic - Page 106
by W H. Wingate - 1865
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The School-master's Guide: Or, a Complete System of Practical Arithmetic ...

Charles Hutton - Arithmetic - 1766 - 214 pages
...and the debt is 135/. 4*. PźQPROBLEM VI. Given the extremes a'nd the common difference, to find 1 . The number of terms. RULE. Divide the difference of the extremes by the common difference, add i to the quotient, and the fum }vill be the number of terms. 2. The fum of the feries. Having found...
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Arithmetical Collections and Improvements: Being a Complete System of ...

Anthony Birks, John Birks - Arithmetic - 1766 - 640 pages
...difference. Which added to each day's journey, PROPOSITION V. The two extremes, and the common excefs given, to find the number of terms. RULE. Divide the difference of the two extremes by the common excefs, the quotient plus unity is the number of terms. ┐k 2 8. A gives...
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A Compendium of Practical Arithmetick

John Thomas Hope - Arithmetic - 1790 - 430 pages
...and the whole diftancc 155 coli from Calcutta. PROPOSITION V. The two extremes and the common excefs given to find the number of terms. RULE. Divide the difference of the two extremes by the common exceli, the quotient plus unity is the number of terms. (l) A man going...
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The Tutor's Assistant Modernised: Or, A Regular System of Practical ...

Thomas Peacock - Arithmetic - 1791 - 302 pages
...find the common difference ? Anf. iiy, , # PROBLEM III. The firft term, the laft term, and the common difference being given, to find the number of terms. RULE. Divide the difference of the extreme╗ by the common difference, and add i to the quotient for the anfwer, E XA MP LE S. 1. The...
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The New Complete System of Arithmetic: Composed for the Use of the Citizens ...

Nicolas Pike - Arithmetic - 1802 - 350 pages
....iboo+i X 1000 " / =500500 Anfwer. 2 PROBLEM 3. Given the extremis and the common dtffsr~ fnce, to Jind the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. I. The extremes are...
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The Arithmetical Magazine, Or, Mercantile Accountant: Adapted to the ...

William M. Finlay - Accounting - 1803 - 272 pages
...18, then 36-7-18=2 common dif. PROBLEM V. Given the first term, the last term, and common difference, to find the number of terms. RULE.— •Divide the...difference of the extremes by the common difference— Jhe quotient + lj "╗˝u be the number of terms required. EXAMPLE. Given the first, 7 the last, S l...
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A Complete Treatise on Arithmetic, Rational and Practical: Wherein the ...

Paul Deighan - Arithmetic - 1804 - 504 pages
...10+15+20, &c. the whole debt╗ 275!. Proportion 3. When the two extremes and common difference are gjven, to find the number of terms. Rule. Divide the difference of the :wo extremes by the common difference or excels ; add unity or i to the quotient, and thcrfani will...
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The Accomplished Tutor; Or, Complete System of Liberal Education ..., Volume 1

Thomas Hodson - Arithmetic - 1806 - 502 pages
...quotient 2 is the common difference. PROBLEM II. Having the two extremes and the common difference, to find the number of terms. Rule. Divide the difference of the extremes by the com- VOL. I. li own mon difference, and i added to the quotient will be the number of terms. Example...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - Arithmetic - 1806 - 342 pages
...and what must each Payment be ? PROPOSITION III. When the two Extremes and the common Difference are given, to find the Number of Terms. RULE. Divide the Difference of the two Extremes by the common Excess or Difference ; add Unity or 1 to the Quotient, and the Sum will...
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The New Complete System of Arithmetick: Composed for the Use of the Citizens ...

Nicolas Pike - Arithmetic - 1807 - 370 pages
...? 1000+ i X 1000 =500500 Anf<wer. 2 PROBLEM 3 Given the extremes and the common difference, tojlnd the number of terms. RULE — Divide the difference of the extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. i. The extremes are...
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