 Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.  The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
 | Charles Hutton - Arithmetic - 1766 - 214 pages
...and the debt is 135/. 4*. P«QPROBLEM VI. Given the extremes a'nd the common difference, to find 1 . The number of terms. RULE. Divide the difference of the extremes by the common difference, add i to the quotient, and the fum }vill be the number of terms. 2. The fum of the feries. Having found... | |
 | Anthony Birks, John Birks - Arithmetic - 1766 - 640 pages
...difference. Which added to each day's journey, PROPOSITION V. The two extremes, and the common excefs given, to find the number of terms. RULE. Divide the difference of the two extremes by the common excefs, the quotient plus unity is the number of terms. ¿k 2 8. A gives... | |
 | John Thomas Hope - Arithmetic - 1790 - 430 pages
...and the whole diftancc 155 coli from Calcutta. PROPOSITION V. The two extremes and the common excefs given to find the number of terms. RULE. Divide the difference of the two extremes by the common exceli, the quotient plus unity is the number of terms. (l) A man going... | |
 | Thomas Peacock - Arithmetic - 1791 - 302 pages
...find the common difference ? Anf. iiy, , # PROBLEM III. The firft term, the laft term, and the common difference being given, to find the number of terms. RULE. Divide the difference of the extreme» by the common difference, and add i to the quotient for the anfwer, E XA MP LE S. 1. The... | |
 | Nicolas Pike - Arithmetic - 1802 - 350 pages
....iboo+i X 1000 " / =500500 Anfwer. 2 PROBLEM 3. Given the extremis and the common dtffsr~ fnce, to Jind the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. I. The extremes are... | |
 | William M. Finlay - Accounting - 1803 - 272 pages
...18, then 36-7-18=2 common dif. PROBLEM V. Given the first term, the last term, and common difference, to find the number of terms. RULE.— •Divide the...difference of the extremes by the common difference— Jhe quotient + lj "»ñu be the number of terms required. EXAMPLE. Given the first, 7 the last, S l... | |
 | Paul Deighan - Arithmetic - 1804 - 504 pages
...10+15+20, &c. the whole debt» 275!. Proportion 3. When the two extremes and common difference are gjven, to find the number of terms. Rule. Divide the difference of the :wo extremes by the common difference or excels ; add unity or i to the quotient, and thcrfani will... | |
 | Thomas Hodson - Arithmetic - 1806 - 502 pages
...quotient 2 is the common difference. PROBLEM II. Having the two extremes and the common difference, to find the number of terms. Rule. Divide the difference of the extremes by the com- VOL. I. li own mon difference, and i added to the quotient will be the number of terms. Example... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...and what must each Payment be ? PROPOSITION III. When the two Extremes and the common Difference are given, to find the Number of Terms. RULE. Divide the Difference of the two Extremes by the common Excess or Difference ; add Unity or 1 to the Quotient, and the Sum will... | |
 | Nicolas Pike - Arithmetic - 1807 - 370 pages
...? 1000+ i X 1000 =500500 Anf<wer. 2 PROBLEM 3 Given the extremes and the common difference, tojlnd the number of terms. RULE — Divide the difference of the extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. i. The extremes are... | |
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