Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
| Samuel Webber - Mathematics - 1808 - 466 pages
...distance 366 miles. PR0BLEM III. Given thefirst term, the last term, and the common difference^ tofmd **the number of terms. RULE.* Divide the difference of the extremes by the common difference,** and the quotient, increased by 1, is the number of terms required. * By the last problem, the difference... | |
| Nicolas Pike - Arithmetic - 1809 - 312 pages
...ICOO+IXIOOO 5=500500 Ans. 2PROBLEM III. Giventhtextremtf -and the common difference> to find the numbir **of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increafed by i wilt be the number of. terms required. EXAMPLES. i. The extremes are... | |
| Samuel Webber - Arithmetic - 1812 - 260 pages
...increase 5, distance 366 miles. PROBLEM 3. Given the first term, the last term, and the common difference^ **to find the number of terms. % RULE.* Divide the difference of the extremes by the common** dlf* By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
| Nathan Daboll - Arithmetic - 1813 - 242 pages
...difference, and 912/. the wholt debt. PROBLEM III. Given the first term, last term, and common difference, tc **find the number of terms. RULE. — Divide the difference of the extremes by the** commot difference, and the quotient increased by 1 is the number of terms EXAMPLES. 1 . If the extremes... | |
| Nathan Daboll - Arithmetic - 1815 - 250 pages
...difference, and 912L the wholf debt. PROBLEM III. Givea the first term, last term, and common difference, **to find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by 1 is the number »f terras. EXAMPLE8. 1. If the extremes be 3 and 45,... | |
| Charles Vyse - Arithmetic - 1815 - 340 pages
...and what must each payment be ? PROPOSITION IIL When the two extremes and the common difference are **given, to find the number of terms. RULE. , . Divide the difference of the** two extremes by the common excess or difference ; add unity or 1 to the quotient, and the sum will... | |
| Arithmetic - 1818 - 264 pages
...miles, and the distance of journey 180 miles. PROBLEM III. The two extremes and the common difference **given, to find the number of terms. RULE. Divide the difference of the extremes by the common** diffenence, and the quotient, increased by 1, is the number of term* inquired. EXAMPLES. 1. If the... | |
| Nathan Daboll - Arithmetic - 1818 - 246 pages
...difference, andQlZl. theivhoh debt. PROBLEM HI. / ' Giyeji the first term, last term, aad common difference, **to' find the number of terms. RULE. Divide the difference of the extremes by the common difference,** and the quotient increased by 1 is the number of terms. ; EXAMPLES. 1. If the extremes be 3 and 45,... | |
| Beriah Stevens - Arithmetic - 1822 - 436 pages
...greatest 1 . 12 X 17=204, and 204+4=208 Ans. PROBLEM 4lh. The first term, the last terra, and common **difference being given, to find the number of terms. RULE. Divide the difference of the** first and last by the common difference, and the quotient plus l, is the number of terms, by theoT... | |
| Nicolas Pike - Arithmetic - 1822 - 538 pages
...1+2+3+4+5+6+7+0=— =36. 2 PROBLEM III. . . • Given the extremes and the common difference, to find ifie **number of terms. RULE.* Divide the difference of the extremes by the common difference,** and the quotient increased by 1 will be the number of terms required. EXAMPLES. 1st. The extremes are... | |
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