 Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.  The parallel arithmetic - Page 106by W H. Wingate - 1865Full view - About this book
 | Samuel Webber - Mathematics - 1808 - 466 pages
...distance 366 miles. PR0BLEM III. Given thefirst term, the last term, and the common difference^ tofmd the number of terms. RULE.* Divide the difference of the extremes by the common difference, and the quotient, increased by 1, is the number of terms required. * By the last problem, the difference... | |
 | Nicolas Pike - Arithmetic - 1809 - 312 pages
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 | Samuel Webber - Arithmetic - 1812 - 260 pages
...increase 5, distance 366 miles. PROBLEM 3. Given the first term, the last term, and the common difference^ to find the number of terms. % RULE.* Divide the difference of the extremes by the common dlf* By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...difference, and 912/. the wholt debt. PROBLEM III. Given the first term, last term, and common difference, tc find the number of terms. RULE. — Divide the difference of the extremes by the commot difference, and the quotient increased by 1 is the number of terms EXAMPLES. 1 . If the extremes... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...difference, and 912L the wholf debt. PROBLEM III. Givea the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number »f terras. EXAMPLE8. 1. If the extremes be 3 and 45,... | |
 | Charles Vyse - Arithmetic - 1815 - 340 pages
...and what must each payment be ? PROPOSITION IIL When the two extremes and the common difference are given, to find the number of terms. RULE. , . Divide the difference of the two extremes by the common excess or difference ; add unity or 1 to the quotient, and the sum will... | |
 | Arithmetic - 1818 - 264 pages
...miles, and the distance of journey 180 miles. PROBLEM III. The two extremes and the common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common diffenence, and the quotient, increased by 1, is the number of term* inquired. EXAMPLES. 1. If the... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...difference, andQlZl. theivhoh debt. PROBLEM HI. / ' Giyeji the first term, last term, aad common difference, to' find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. ; EXAMPLES. 1. If the extremes be 3 and 45,... | |
 | Beriah Stevens - Arithmetic - 1822 - 436 pages
...greatest 1 . 12 X 17=204, and 204+4=208 Ans. PROBLEM 4lh. The first term, the last terra, and common difference being given, to find the number of terms. RULE. Divide the difference of the first and last by the common difference, and the quotient plus l, is the number of terms, by theoT... | |
 | Nicolas Pike - Arithmetic - 1822 - 536 pages
...1+2+3+4+5+6+7+0=— =36. 2 PROBLEM III. . . • Given the extremes and the common difference, to find ifie number of terms. RULE.* Divide the difference of the extremes by the common difference, and the quotient increased by 1 will be the number of terms required. EXAMPLES. 1st. The extremes are... | |
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