 | George Wentworth, David Eugene Smith - Algebra - 1913 - 478 pages
...of the root for a complete divisor. Multiply the complete divisor by this next figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Proceed in this manner until all the periods have been thus annexed.... | |
 | George Albert Wentworth, David Eugene Smith - Algebra - 1913 - 310 pages
...of the root for a complete divisor. Multiply the complete divisor by this next figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Proceed in this manner until all the periods have been thus annexed.... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...for a complete divisor the figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 22 1' 1 .56' 25 |1.25 245 56 44 12 12 25 25 1. When the number is... | |
 | Frank Eugene Kidder - Architecture - 1915 - 1856 pages
...also in place of the cipher in the divisor. Multiply this final divisor by tli number in the quotient just found, subtract the product from the dividend and to the remainder bring down the next period for a new dividend and proceed as before. If it should be found that the... | |
 | George William Myers, George Edward Atwood - Algebra - 1916 - 362 pages
...to the root and also to the divisor. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Repeat this process, using all the periods. Exercise 143 Find the square... | |
 | Frank Eugene Kidder - Architecture - 1921 - 1944 pages
...and'also'in place of the cipher in the divisor. Multiply this final divisor by the number in the quotient just found, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend and proceed as before. If it should be found that the... | |
 | Mary Texanna Loomis - Radio - 1927 - 904 pages
...and also at the right of the trial divisor. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. divisor, and proceed ad before until all the periods have been used.... | |
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Add to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 
