 | Edward Brooks - Algebra - 1888 - 344 pages
...their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 time» the square of the root now found, regarded as tens, for... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 444 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root ßgure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all the periods... | |
 | George Albert Wentworth - Arithmetic - 1889 - 434 pages
...of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed.... | |
 | James William Nicholson - Arithmetic - 1889 - 408 pages
...to form the complete divisor. IV. Afultiply the complete divisor by the second figure of the root; subtract the product from the dividend, and to the remainder annex the next period for a dividend. V. Proceed with the second, and with each succeeding dividend, in the same... | |
 | John Groesbeck - 1891 - 426 pages
...so found for a complete divisor. 5. Multiply the complete divisor by the second figure in the root. Subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Then proceed as before until all the periods have been used. Note 1.... | |
 | William James Milne - Arithmetic - 1892 - 440 pages
...for a complete divisor the Jigure last found, multiply this divisor by the last Jigure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus.... | |
 | William James Milne - Algebra - 1894 - 214 pages
...to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The... | |
 | William James Milne - Algebra - 1894 - 216 pages
...to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The... | |
 | George Edward Atwood - Arithmetic - 1894 - 396 pages
...to the root and also to the divisor. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in the same manner until all the periods have been used.... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...divisor, and the sum will be the true divisor. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods... | |
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Add to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 
