 | William Seneca Sutton - 1896 - 342 pages
...sum add the square, of the last root-figure. (v) Multiply the true divisor by the last root-figure; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. (vi) Square the sum of the first root-figure considered as hundreds... | |
 | George Albert Wentworth - Arithmetic - 1896 - 490 pages
...of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this .manner until all the groups have been thus annexed.... | |
 | George Albert Wentworth - Arithmetic - 1897 - 480 pages
...of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed.... | |
 | George Albert Wentworth - 1898 - 424 pages
...of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed.... | |
 | George Albert Wentworth - Arithmetic - 1898 - 424 pages
...of the root for a- complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed.... | |
 | George Albert Wentworth - Arithmetic - 1898 - 424 pages
...of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed.... | |
 | George Edward Atwood - Arithmetic - 1899 - 392 pages
...to the root and also to the divisor. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in the same manner until all the periods have been used.... | |
 | William James Milne - Algebra - 1901 - 462 pages
...to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. Tlie... | |
 | Edward Brooks - Algebra - 1901 - 248 pages
...their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...divisor for the complete divisor. 4. Multiply the complete divisor by the second figure of the root ; subtract the product from the dividend, and to the remainder annex the next period for another dividend. 5. Double the part of the root already found for another trial divisor,... | |
| |
Add to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 
