 | Alan Sanders - Geometry - 1903 - 396 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let A BCD be any parallelogram BE C and DE be its altitude. r To Prove ABCD = AD x DE. Proof. Draw AF _L... | |
 | Fletcher Durell - Geometry, Solid - 1904 - 232 pages
...side. BOOK IV. 383. The area of a rectangle is equal to the product of its base by its altitude. 385. The area of a parallelogram is equal to the product of its base by its altitude. 389. The area of a triangle is equal to one-half the product of its base by its... | |
 | George Albert Wentworth - Geometry - 1904 - 496 pages
...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. CF CE A b DA b D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
 | Fletcher Durell - Geometry - 1911 - 553 pages
...Find, in square feet, the area of a rectangle 8 yds. long and 5 ft. wide. PROPOSITION IV. THEOREM 385. The area of a parallelogram is. equal to the product of its base by its altitude. K__B__ pa A b D Given the ZZ7 ABCD with the base AD (denoted by b) and the altitude... | |
 | Fletcher Durell - Geometry, Plane - 1904 - 382 pages
...area of a rectangle 8 yds. long and 5 ft. wide. BOOK IV. PLANE GEOMETRY PROPOSITION IV. THEOREM 385. The area of a parallelogram is equal to the product of its base by its altitude. KB FC Given the ZZ7 ABCD with the base AD (denoted by 6) and the altitude DF... | |
 | George Clinton Shutts - 1905 - 260 pages
...fractional number of times in the base and altitude the same rule is reached. PROPOSITION IV. 330. Theorem. The area of a parallelogram is equal to the product of its base and altitude. Suggestion. § 323 and § 326. PROPOSITION V. 331. Theorem. The area of a triangle is equal to one-half... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...resulting figure will be a rectangle of the same area, base, and altitude as the BASE parallelogram. The area of a parallelogram is equal to the product of its base and altitude, expressed in like units. ' ' " and Written Exercises Estimate results mentally before solving. Find... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry, Plane - 1915 - 320 pages
...rt.AAED = rt.ABFC. Why? ABFD - AAED = nABFE. ABFD - ABFC = OABCD. • .'. nABFE = UABCD. Why? 355. Theorem. The area of a parallelogram is equal to the product of its base and altitude. As a formula, A = bh. This follows from §§ 346 and 354. 356. Theorem. The altitude of a parallelogram... | |
 | John Wesley Young, Albert John Schwartz - Geometry, Modern - 1915 - 248 pages
...altitude is then the perpendicular distance between the base and the opposite side (§§ 228, 229). 348. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. E n FIG. 162. Given the parallelogram ABCD with the base 6 and the altitude h.... | |
 | Edward Rutledge Robbins - Geometry, Plane - 1915 - 282 pages
...times as long as it is wide, how many square yards will the field contain? PROPOSITION IV. THEOREM 359. The area of a parallelogram is equal to the product of its base by its altitude. FD EC Given : O ABCD, with base b and j altitude h. To Prove : Area of ABCD =... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
