 | Arthur Schultze - 1901 - 260 pages
...rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. TTie area of a parallelogram is equal to the product of its base and its altitude. A Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To frnn.e... | |
 | Samuel Wesley Baird - Arithmetic - 1901 - 174 pages
...Find the cost of cementing a cellar bottom 54 ft. .long and 18| ft. wide, at 62|/ a square yard. Since the area of a parallelogram is equal to the product of its length and breadth, either side will equal the area divided by the other side. 6. A blackboard has... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let A BCD be any parallelogram and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD,... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. K a Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE =... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 312 pages
...rectangle? How does the altitude of one ,, _' -F compare with that of the A Jit JJ , other? Principle. — The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...the rectangle? How does the altitude of one ( , j. compare with that of the other? Principle.—The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
 | George Albert Wentworth - Geometry, Solid - 1902 - 248 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403.... | |
 | American School (Chicago, Ill.) - Engineering - 1903 - 390 pages
...195. Corollary. The area of a square is equal to the square of one of its sides. THEOREn LXIV. Ip6. The area of a parallelogram is equal to the product...its base and altitude. Let ABCD be a parallelogram leaving its altitude DF equal to a and its base AD equal to ft. To prove that ABCD = ax&: Draw AE perpendicular... | |
 | Alan Sanders - Geometry - 1903 - 392 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD, meeting... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
