| George Albert Wentworth - Geometry - 1899 - 498 pages
...by dividing the figure into squares, each T~ BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE OF B GE A b DAI) D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
| William James Milne - Geometry, Modern - 1899 - 258 pages
...=0= A AD F + A BED ; that is, ABCD =0= ABEF. Therefore, etc. QED MILNE'S GEOM. — 12 332. Cor. I. The area of a parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases... | |
| Metal-work - 1901 - 548 pages
...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two opposite sides AB and... | |
| Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and an equal altitude.... | |
| Edward Brooks - Geometry, Modern - 1901 - 278 pages
...constructed on the lines as sides. Similarly the second power of a number is called the square of the number. PROPOSITION V. — THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Given. — Let ABCD be any parallelogram, AB its base, and BE its altitude. To... | |
| Arthur Schultze - 1901 - 392 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h.... | |
| Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...303. (6) The area of any rectangle is equal to the product of its base and its altitude. § 304. (7) The area of a parallelogram is equal to the product of its base and its altitude. § 305. (8) The area of a square is equal to the square of any one of its sides. § 307.... | |
| Arthur Schultze - 1901 - 260 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
| Alan Sanders - Geometry, Modern - 1901 - 260 pages
...units) in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY. The area of any parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram f BEC and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD, meeting... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...rectangle is 360 square inches, and its base ia 4 yds. Find the altitude. PROPOSITION IV. THEOREM 341. TJie area of a parallelogram is equal to the product of its base and its altitude. Hyp. ABCD is a parallelogram, having the base AB — b, and the altitude BE = h. To prove... | |
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