| 1885 - 608 pages
...Show that the sum of the interior angles of any rectilineal figure together witli four right angles, **is equal to twice as many right angles as the figure has sides.** 5. Prove that the opposite sides and angles of a parallelogram are equal to one another, and that the... | |
| Webster Wells - Geometry - 1886 - 392 pages
...angles is expressed by 2 R x (n — 2) , or 2 nR — 4 R. That is, the sum of the angles of a polygon **is equal to twice as many right angles as the figure, has sides, less four right angles.** PROPOSITION XLVII. THEOREM. 149. If the sides of a polygon are produced so as to form an exterior angle... | |
| William Davis Haskoll - Hydrographic surveying - 1886 - 354 pages
...every station on a survey. In any polygon, regular or irregular, the sum of all the interior angles **is equal to twice as many right angles as the figure has sides, less four right angles.** As observed above, and as may be seen by referring to the figure 52, whether we consider the regular... | |
| Richard Anthony Proctor - Geometry - 1887 - 202 pages
...produced to meet, the angles formed by these lines, together with eight right angles, are together **equal to twice as many right angles as the figure has sides.** 139. AP, BP, and CP are the internal bisectors of the angles of the triangle ABC. AP is produced to... | |
| Bennett Hooper Brough - Mine surveying - 1888 - 366 pages
...accuracy of the survey, as the interior angles of the polygon together with four right angles should be **equal to twice as many right angles as the figure has sides.** The interior angles of a traverse may be found from the bearings or courses by the following rules... | |
| E. J. Brooksmith - Mathematics - 1889 - 354 pages
...right angles : that the sum of the angles of any rectilineal figure together with four right angles **is equal to twice as many right angles as the figure has sides** : and that the sum of the distances of any point from the angular points of the figure is greater than... | |
| Edward Albert Bowser - Geometry - 1890 - 420 pages
...2 rt. Zs (n — 2) = 2n rt. Zs — 4 rt. Zs. Therefore, the sum of the angles of a polygon is also **equal to twice as many right angles as the figure has sides, less four right angles.** 149. COR. 2. The sum of the angles of a quadrilateral is equal to two right angles taken (4 — 2)... | |
| James Hutchens Baker - Psychology - 1890 - 266 pages
...case of a particular polygon that the sum of its interior angles, together with four right angles, **is equal to twice as many right angles as the figure has sides** — and conclude that the law holds good of all polygons. In calculating the terms of a ' Mill's Logic,... | |
| John Fry Heather - Geometry, Modern - 1890 - 252 pages
...63. THEOE. 6. All the interior angles of any rectilinieal figure together with four right angles, are **equal to twice as many right angles as the figure has sides** (Euc. I. 32. Cor. 1). Hence the angles of a regular polygon are each equal to the quotient obtained... | |
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