| Cambridge univ, exam. papers - 1856 - 200 pages
...Prove that all the internal angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides;** and that all the external angles are together equal to four right angles. In what sense are these propositions... | |
| Frederick Walter Simms - Leveling - 1856 - 258 pages
...together all the internal angles, marked by dotted segments of circles; and subtract their sum from **twice as many right angles as the figure has sides, less four,** for the angle db e. Example. — Let the angles denoted by the dotted segments at the different letters... | |
| Euclides - 1856 - 168 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are **equal to twice as many right angles as the figure has sides.** XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
| Adrien Marie Legendre - Geometry - 1857 - 444 pages
...are triangles in the figure ; that is, as many times as there are sides, less two. But this product **is equal to twice as many right angles as the figure has sides, less four right angles.** Cor. 1. The sum of the interior angles in a quadrilateral is equal to two right angles multiplied by... | |
| William Mitchell Gillespie - Surveying - 1857 - 538 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles **is equal to twice as many right angles, as the figure has sides less** two ; since the figure can be divided into that number of triangles. Hence this common rule. " Calculate... | |
| W. Davis Haskoll - Civil engineering - 1858 - 422 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together **equal to twice as many right angles as the figure has sides, less four.** On this is based the theory of the traverse, of which further explanation will be given in another... | |
| Elias Loomis - Conic sections - 1858 - 256 pages
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are **equal to twice as many right angles as the figure has sides,** wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ;... | |
| Horatio Nelson Robinson - Geometry - 1860 - 472 pages
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must be **equal to twice as many right angles as the figure has sides.** But the sum of these angles contains the sum of four right angles about the point p ; taking these... | |
| Sir Norman Lockyer - Electronic journals - 1880 - 668 pages
...XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are **equal to twice as many right angles as the figure has sides.** In the new notation we would say that the sum of the interior angles of the polygon is equal to a number... | |
| Oxford univ, local exams - 1880 - 394 pages
...circle. 2. All the interior angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides.** 3. If the square described on one side of a triangle be equal to the squares described on the other... | |
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