 | International Correspondence Schools - Arithmetic - 1904 - 656 pages
...and add the result to the first trial divisor to form the first complete divisor. Multiply the first complete divisor by the second figure of the root, and subtract the result from the first dividend in the third column. Add the second figure of the root to the number... | |
 | International Correspondence Schools - Arithmetic - 1906 - 576 pages
...and add the result to the first trial divisor to form the first complete divisor. Multiply the first complete divisor by the second figure of the root, and subtract the result from the first dividend in the third column. Add the second figure of the root to the number... | |
 | Samuel Hamilton - Arithmetic - 1909 - 398 pages
...to the remainder. Double the root found for a trial divisor. Divide the remainder, omitting the last figure, by this trial divisor, and annex the quotient...proceed as above until all the periods have been used. NOTE.-—When a naught occurs in the root, annex a naught to the trial divisor, bring down another... | |
 | Correspondence schools and courses - 1909 - 886 pages
...and add the result to the first trial divisor to form the first complete divisor. Multiply the first complete divisor by the second figure of the root, and subtract the result from the first dividend in the third column. Add the second figure of the root to the number... | |
 | Thomas J. Foster - Coal mines and mining - 1916 - 1230 pages
...considered as tens, also the square of the second figure; the result •will be the complete divisor, V. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. VI. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Eugene Henry Barker - Mathematics - 1920 - 264 pages
...figure, by this trial divisor, and annex the quotient to the root and also to the trial divisor. (5) Multiply the complete divisor by the second figure...root and subtract the product from the remainder. (6) Double the part of the root already found, for another trial divisor, and proceed as before. (7)... | |
 | William Ledley Vosburgh, Frederick William Gentleman, Jasper Ole Hassler - Mathematics - 1924 - 312 pages
...figure, by this trial divisor, and annex the quotient to the trial divisor and also to the root. (c) Multiply the complete divisor by the second figure...root, and subtract the product from the remainder. i (d) Double the root already found for another trial divisor, and proceed as above until all the periods... | |
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Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 
