 | Joseph Ficklin - Arithmetic - 1881 - 412 pages
...first, considered as tens, and the square of the second figure. The result will be the complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. 4. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Daniel W. Fish - Arithmetic - 1883 - 364 pages
...considered as tens, also the square of the second figure, the result will be the complete divisor. 5. Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 6. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Daniel W. Fish - Arithmetic - 1883 - 348 pages
...of the second figure, the result will be the complete divisor. 5. Multiply the complete divisor bу the second figure of the root and subtract the product from the dividend. 6. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Edward Brooks - Algebra - 1888 - 344 pages
...result ; annex the quotient to the root and also to the trial divisor for a complete divisor. Mubtiply the complete divisor by the second figure of the root, and subtract the product from the dividend. IV. If there are other terms of the polynomial remaining, proceed in a similar manner until... | |
 | John Bernard Clarke - Algebra - 1889 - 566 pages
...twice the root already found. Annex the quotient to the root and to the divisor. Multiply the augmented divisor by the second figure of the root and subtract the product from the first remainder. If the product should be greater than the first remainder, diminish the number of... | |
 | Thomas J. Foster - Coal mines and mining - 1891 - 444 pages
...considered as tens, aho the square of the sscond figure ; the result will be the complete divisor. . V. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. VI. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Henry Holmes Belfield - Arithmetic - 1891 - 362 pages
...5. Annex the second figure of the root to the trial divisor, for a complete divisor ; multiply this divisor by the second figure of the root, and subtract the product from the trial dividend. INVOLUTION AND EVOLUTION. new trial divisor, and proceed as before until every period... | |
 | Bothwell Graham - Arithmetic - 1895 - 240 pages
...tens, and also the square of the second figure. The sum will be the complete divisor, which multiply by the second figure of the root and subtract the product from the dividend. Proceed in the same way with the remaining periods (if any) until all are brought down. Point... | |
 | Edward Brooks - Algebra - 1901 - 248 pages
...by the result ; annex the quotient ta the root and also to the trial divisor for a complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the prodiict from the dividend. , IV. If there are other terms of the polynomial remaining, proceed in... | |
 | Jacob Henry Minick, Clement Carrington Gaines - Business mathematics - 1904 - 412 pages
...second figure of the root, written one figure to the right. Their sum will be the complete divisor. Multiply the complete divisor by the second figure of the root and subtract the product from, the dividend, and to the remainder annex the next period for the next dividend. Take three times the square... | |
| |
Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 
