 | Joseph Ficklin - Algebra - 1874 - 446 pages
...figures of the root, also the square of the second figure ; the result will be the confíete divisor. V. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. VI. If there are more periods to be brought down, continue the operation in the sanie manner... | |
 | Daniel W. Fish - Arithmetic - 1874 - 302 pages
...considered as tens, also the square of the second figure, the result will be the complete divisor, V. Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. VI. // there are more periods to be brought down, pro' ceed as before, using the part of... | |
 | Daniel W. Fish - Arithmetic - 1874 - 540 pages
...first considered as tei. the square of the second figure, the result will be the ,,iplete divisor. V. Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. VI. If there are more periods to be brought down, proceed as before, using the part of the... | |
 | Daniel W. Fish - Arithmetic - 1874 - 526 pages
...considered as tens, also the square of the second figure, the result will be the complete divisor. V. Multiply the complete divisor by the second figure of the root and subtract the product from (he dividend. VI. If there are more periods to be brought down, proceed as before, using the part of... | |
 | Albert Newton Raub - Arithmetic - 1877 - 348 pages
...the second figure, add these two results to the trial divisor, and the divisor becomes complete. 5. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. 6. If there be a remainder and any more periods, to this remainder annex the next period,... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...found, and to the result add the square of the figure last found; the sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. If there are any more periods to be brought down, annex the next period to the last remainder,... | |
 | C. Frusher Howard - Ready-reckoners - 1879 - 134 pages
...root by the first, plus the square of the second figure ; the sum will be the complete divisor. 5. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. 6. Continue this process until the exact cube, or a sufficient approximation to it is found,... | |
 | Robert Potts - Algebra - 1879 - 672 pages
...figure of the root. 5. Annex this figure to the trial divisor, and multiply the divisor so increased by the second figure of the root, and subtract the product from the dividend. 6. To this remainder annex the next period to form a new dividend, and find a new trial divisor... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 292 pages
...found, and to the result add the square of the figure last found ; the sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. If there are any more periods to be brought down, annex the next period to the last remainder,... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...found, and to the result add the square of the figure last found ; the sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. If there are any more periods to be brought down, annex the next period to the last remainder,... | |
| |
Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 
