| Edward Atkins - 1877 - 72 pages
...two equal parts. Therefore, the opposite sides, &c. QED Proposition 35. — Theorem. Parallelograms **upon the same base, and between the same parallels, are equal to one another. Let the** parallelograms ABCD, EBCF be on the same base BC, and between the same parallels AF, BC ; The parallelogram... | |
| William George Spencer - Geometry - 1876 - 118 pages
...make two triangles that shall be equal to each other, and yet not similar ? 137. Can you show that all **triangles upon the same base and between the same parallels are equal to one another** ? 138. Can you place a circle, whose radius is \\ inch, so that its circumference may touch two points... | |
| William George Spencer - Geometry - 1877 - 108 pages
...make two triangles that shall be equal to each other, and yet not similar ? 137. Can you show that all **triangles upon the same base and between the same parallels are equal to one another** ? 138. Can you place a circle, whose radius is 1J inch, so that its circumference may touch two points... | |
| D. Tierney - 1877 - 126 pages
...not intersect, and therefore the construction for the triangle required would fail. 2. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** Shew that if two triangles have two sides of the one equal to two sides of the other, each to each,... | |
| Alfonzo Gardiner - 1878 - 146 pages
...= _. 7. The difference of two numbers is 14, and their sum is 48 : find the numbers. 8. Prove that **triangles upon the same base, and between the same parallels, are equal to one another.** 9. What do you mean by the " complements of a parallelogram " and by " applying a parallelogram to... | |
| J T. Amner - 1878 - 226 pages
...equal to two right angles. What ratio does the angle of a regular hexagon bear to a right angle ? 2. **Triangles upon the same base and between the same parallels are equal.** A line drawn through the middle points of the sides of a triangle is parallel to the base. 3. In any... | |
| Thomas Hunter - Geometry, Plane - 1878 - 142 pages
...same reason EFGH is equal to ABGH. Hence ABCD and EFGH are equal (Ax. 1). PROPOSITION VIII.—THEOREM. **Triangles upon the same base, and between the same parallels, are equal** ABC and ABD have the same base, AB, and be between the same parallels, AB and CD; then will these two... | |
| James Hamblin Smith - Euclid's Elements - 1879 - 378 pages
...EBCH=CJEFGH, I. 35. v they are on the same base EH and between the same || s ; .: lUABCD=OEFGH. QED **PROPOSITION XXXVII. THEOREM. Triangles upon the same...between the same parallels, are equal to one another.** O Let A a ABC, DBC be on the same base BC and between the same \\a AD, BC. Then must A ABC= &DBC. From... | |
| Great Britain. Civil Service Commission - 1879 - 622 pages
...same side ; and also the two interior angles on the same side together equal to two right angles. 3. **Triangles upon the same base and between the same parallels are equal to one another. Let** ABC, ABD, be two equal triangles upon the same base AB, and on opposite sides of it ; if CD be joined... | |
| Moffatt and Paige - 1879 - 474 pages
...ACD B. Therefore, the opposite sides and angles, etc. . QED Proposition XXXV. Theorem. Parallelograms **upon the same base, and between the same parallels, are equal to one another. Let the** parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, B C. Then the... | |
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