| Great Britain. Admiralty - Geometry - 1846 - 130 pages
...two = parts. Wherefore the opposite sides and angles, &c. PROP. XXXIV. THEOR. 35. lEu. Parallelograms **upon the same base, and be-tween the same parallels, are equal to one another.** FA DEFAEDF \ . If the sides AD, DF, of the / — 7"" ABCD, DBCF, opp. to RC the base, be terminated... | |
| John Playfair - Euclid's Elements - 1846 - 332 pages
...adjacent angles of a parallelogram is equal to two right angles. PROP. XXXV. THEOR. Parallelograms **upon, the same base and between the same parallels, are equal to one another.** > (SEE THE 2d AND 3d FIGURES.) 34 If the sides AD, DF of the parallelograms ABCD, DBCF opposite to... | |
| London univ - 1846 - 326 pages
...exterior angles of any rectilineal figure are together equal to four right angles. 6. Parallelograms **upon the same base and between the same parallels are equal to one another.** 7. Show that the complements of the parallelograms which are about the diameter of any .parallelogram... | |
| Great Britain. Admiralty - Geometry - 1846 - 130 pages
...•=• parts. Wherefore the opposite sides and angles, &c. PROP. XXXIV. THEOR. 3s. lEu. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** PROP. XXXIV. FADE F \ . If the sides AD, DF, of the 1=1™ ABCD, DBCF, opp. to BC the base, be terminated... | |
| Euclides - 1847 - 128 pages
...KLNC (Ax.2) = Dm BMNC. Wherefore the sum of the areas &c. — QED PEOP. XXXVII. THEOR. GEN. ENUN. — **Triangles upon the same base, and between the same parallels, are equal to one another.** PART. ENUN. — Let the A ABC, DBC be upon the same base BC, and between the same || s AD, BC ; then... | |
| Thomas Gaskin - Geometry, Analytic - 1847 - 301 pages
...CAMBRIDGE, Nov. 1847. GEOMETRICAL PROBLEMS. ST JOHN'S COLLEGE. DEC. 1830. (No. I.) 1. PARALLELOGRAMS **upon the same base and between the same parallels are equal to one another.** 2. Of unequal magnitudes,, the greater has a greater ratio to the same than the less. 3. If the diameter... | |
| Euclides - 1848 - 52 pages
...diameter bisects them, that is, divides them into two equal parts. PROP. XXXV. THEOREM. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** PROP. XXXVI. THEOREM. PROP. XXXVII. THEOREM. Triangles upon the same base anti between the same parallels,... | |
| Great Britain. Council on Education - Education - 1848
...point out how the construction fails when that condition is not fulfilled. 2. Prove that parallelograms **upon the same base and between the same parallels are equal to one another.** Shew hence that the area of a parallelogram is properly measured by the product of the numbers that... | |
| J. Goodall, W. Hammond - 1848 - 388 pages
...point out how the construction fails when that condition is not fulfilled. 2. Prove that parallelograms **upon the same base and between the same parallels are equal to one another.** Show hence that the area of a parallelogram is properly measured by the product of the numbers that... | |
| Great Britain. Committee on Education - Education - 1848 - 598 pages
...point out how the construction fails when that condition is not fulfilled. 2. Prove that parallelograms **upon the same base and between the same parallels are equal to one another.** Shew hence that the area of a parallelogram is properly measured by the product of the numbers that... | |
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