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" Multiply as in whole numbers, and point off as many decimal places in the product as there are decimal places in the multiplicand and multiplier, supplying the deficiency, if any, by prefixing ciphers. "
American Comprehensive Arithmetic - Page 107
by Middlesex Alfred Bailey - 1897 - 320 pages
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Bradbury's, Eaton's Practical Arithmetic: Combining Oral and Written Exercises

William Frothingham Bradbury - 1885 - 416 pages
...product directly under the figure of the multiplier which produces it. 3. Add these partial products and point off as many decimal places in the product as there arc in the multiplicand, and the result mill be the true product. 62. PROOF. Multiply tJie multiplier...
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Standard Elementary Arithmetic: Combining Oral and Written Exercises

Edward Sylvester Ellis - Arithmetic - 1886 - 200 pages
...-riJo x Tfo = -nfi&W = -00255. Rule for Multiplication of Decimals.—Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in...
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The New Practical Arithmetic

Waite A. Schoemaker - Arithmetic - 1887 - 454 pages
...places in the product with the number of decimal places in both factors. Make a rule for pointing off. Point off as many decimal places in the product as there are in both factors. Form of Work. 5. 4.53 .23 1359 906 1.041!) ORAL WORK. 1. .04 of .004 = . Hundredths...
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Elementary Arithmetic: Combining Oral and Written Exercises

Edward Sylvester Ellis - Arithmetic - 1889 - 196 pages
...may be obtained thus : .00255 Bnle for Multiplication of Decimals. — Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in...
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Complete Arithmetic: Combining Oral and Written Exercises

Edward Sylvester Ellis - Arithmetic - 1889 - 370 pages
...1488 744 ,08928 ART. 177. — Rule for Multiplication of Decimals. — Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in...
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First Book of Arithmetic: Uniting Oral and Written Exercises

Emerson Elbridge White - Arithmetic - 1890 - 178 pages
...1000; by 10000. To multiply one decimal by another: — RULE. — Multiply as in the multiplication of integers, and point off as many decimal places in...decimal places in both multiplicand and multiplier. NOTE. — If there be not enough decimal figures in the product, supply the deficiency by prefixing...
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Elementary Arithmetic

John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1893 - 316 pages
...places as there are in both factors. 18. Multiply .253 by .35. ,,-.-, Multiply as in whole numbers, and point off as many decimal places in the product as there are in both multiplicand and mul1265 tiplier. If there are not enough figures in 759 the product to fill...
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The Normal Elementary Arithmetic: Embracing a Course of Easy and Progressive ...

Edward Brooks - Arithmetic - 1893 - 228 pages
...3.3258. From either of these solutions we derive the following RULE. — Multiply as in whole numbers, and point off as many decimal places in the product as there are in both multiplier and multiplicand, prefixing ciphers when necessary. 2. Multiply 15.17 by .18. 3....
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New Practical Arithmetic: In which the Science and Its Applications are ...

Henry B. Maglathlin - 1894 - 370 pages
...is equal to the number of decimal places in both of the factors. BULB. Multiply as in whole numbers, and point off as many decimal places in the product as there are decimal places in the multiplicand and multiplier, supplying the deficiency, if any, by prefixing ciphers. Or, If the...
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A Common School Arithmetic

Bothwell Graham - Arithmetic - 1895 - 240 pages
...Multiply the numerators together as though they were integers. II. To find the denominator of the product. Point off as many decimal places in the product as there are decimal places in both factors, prefixing when necessary zeros to supply the deficiency. 2. Divide 1.25 by .25. PROCESS. EXPLANATION....
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