 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  The Foundations of Higher Arithmetic - Page 63by Benjamin Franklin Sisk - 1905 - 203 pagesFull view - About this book
 | Edward Brooks - Arithmetic - 1876 - 588 pages
...root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend,...remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for a trial divisor, and find the... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...The square of the last figure of the root. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend,...remainder annex the next period for a new dividend. Form, in the same manner, successive divisors, and find corresponding figures of the root ; being careful... | |
 | William Frothingham Bradbury - Algebra - 1877 - 302 pages
...right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, subtract the product from the dividend, and to the...remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to,the trial divisor, and bring down the next period... | |
 | William Frothingham Bradbury - Algebra - 1877 - 280 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
 | William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
 | William Guy Peck - Arithmetic - 1877 - 430 pages
...trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial -figure of the root, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Stoddard A. Felter, Samuel Ashbel Farrand - Arithmetic - 1877 - 496 pages
...the root, also add it to the partial divisor. IV. — Multiply and subtract, as in simple division, and to the remainder annex the next period for a new dividend. Proceed as before until all the periods are exhausted. NOTES. — (1.) It the dividend at any time... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...first left-hand period of the given number. Subtract this product from this first left-hand period, and to the remainder annex the next period for a new dividend. Add the figure of the root just found to the amount in the first column, multiply the sum by the same... | |
 | Joseph Ray - Arithmetic - 1877 - 350 pages
...on the right of the trial divisor. Prie. 2П. 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor,... | |
 | Edward Olney - Algebra - 1878 - 516 pages
...WRITE IT AS THE HIGHEST ORDER IN THE ROOT. SUBTRACT THE SQUARE OF THIS FIGURE FROM THE PERIOD USED, AND TO THE REMAINDER ANNEX THE NEXT PERIOD FOR A NEW DIVIDEND. 3rd. DOUBLE THE HOOT ALREADY FOUND FOR A TRIAL DIVISOR, BY WHICH DIVIDE THE NEW DIVIDEND, REJECTING... | |
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