 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  The Foundations of Higher Arithmetic - Page 63by Benjamin Franklin Sisk - 1905 - 203 pagesFull view - About this book
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...divisor, and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately... | |
 | James B. Dodd - Algebra - 1859 - 368 pages
...and multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root ; subtract the product from the dividend ; and to the remainder affix the next period for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
 | James B. Dodd - Arithmetic - 1859 - 368 pages
...and multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root; subtract the product from the dividend ; and to the remainder affix the next period, for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
 | Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...Multiply tlie true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the number standing... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...root to the trial divisor for a complete divisor ; multiply tlie complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period for a new dividend. V Multiply the last figure of the last complete divisor... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...on the right of the partial divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial... | |
 | James Stewart Eaton - 1862 - 320 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...root to the trial divisor for a complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...root, and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but... | |
 | James Stewart Eaton - Arithmetic - 1864 - 322 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE... | |
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