 | Charles Davies - Geometry - 1854 - 436 pages
...of each as there are sides of the polygon : hence the sum of all the interior and exterior angles, is equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has... | |
 | Thomas Lund - Geometry - 1854 - 520 pages
...But the angles at 0 are equal to four right angles (30 Cor.); .'. all the angles of the polygon are equal to twice as many right angles as the polygon has sides, diminished by four right angles. COR. 1 . Hence, all the angles of a pentagon = 6 right angles ; hexagon... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...exterior angles is equal to four right angles (T. IV.) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. I. In any triangle, the sum of the three angles is equal1 to two right... | |
 | Elias Loomis - Conic sections - 1857 - 242 pages
...equal to two right angles (Prop. II.) ; therefore the sum of all the interior and exterior angles, is equal to twice as many right angles as the polygon has sides ; that is, they are equal to all the interior angles of the polygon, together with four right angles.... | |
 | Education - 1857 - 1266 pages
...alternate sides, also produced, the angles formed by these lines, together with eight right angles are equal to twice as many right angles as the polygon has sides. 4. If two chords intersect in a circle, the difference of their squares is equal to the difference... | |
 | British and foreign school society - 1857 - 548 pages
...alternate sides, also produced, the angles formed by these lines, together with eight right angles, are equal to twice as many right angles as the polygon has sides. 4. If two chords intersect in a circle, the difference of their squares is equal to the difference... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...angles of each of these triangles, is equal to tw» right angles (Prop. XXVII.) ; therefore the sum of the angles of all the triangles, is equal to twice...many right angles as the polygon has sides. But the same angles are equal to the angles of the polygon, together with the angles at the point F, that is,... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...exterior angles is equal to four right angles (T. IV.) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. I. In any triangle, the sum of the three angles is equal to two right... | |
 | Charles Davies - 1863 - 436 pages
...three angles of each of these triangle* is equal to two right angles (Th- xvii) : hence, the sum of th angles of all the triangles is equal to twice as many right asgles as the figure has sidesBut the sum of all the angles about the point P is equal to four right... | |
 | Eli Todd Tappan - Geometry, Modern - 1864 - 288 pages
...among the equal parts. SUM OF THE ANGLES. 433. Theorem. — The sum of all the angles of a polygon is equal to twice as many right angles as the polygon has sides, less two. For the polygon may be divided into as many triangles as it has sides, less two (417); and... | |
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... therefore the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles... 
