 | Sir J. Butler Williams - Geodesy - 1846 - 368 pages
...of all the interior angles of the polygon formed by joining the stations by straight lines will be equal to twice as many right angles as the polygon has sides, wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
 | Charles William Hackley - Geometry - 1847 - 248 pages
...three angles of each of these triangles is equal to two right angles (th. 15) ; therefore, the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point F, which are so many of the angles... | |
 | George Roberts Perkins - Geometry - 1847 - 326 pages
...exterior angles is equal to four right angles (Prop. xxm) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. 1. Jn any triangle, the sum of all the three angles is equal to two... | |
 | Elias Loomis - Conic sections - 1849 - 252 pages
...angles of each of these triangles, is equal to two right angles (Prop. XXVII.); therefore the sum of the angles of all the triangles, is equal to twice...many right angles as the polygon has sides. But the same angles are equal to the angles of the polygon, together with the angles at the point F, that is,... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...of each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again, the sum of all tho interior angles is equal to two right angles, taken as many times, less two,... | |
 | Charles Davies - Geometry - 1850 - 238 pages
...three angles of each of these triangles is equal to two right angles (Th. xvii) : hence, the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point P is equal to four right angles (Th.... | |
 | Charles Davies - Geometry - 1850 - 218 pages
...three angles of each of these triangles is equal to two right angles (Th. xvii) : hence, the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point P is equal to four right angles (Th.... | |
 | Charles Davies - Geometry - 1886 - 340 pages
...three angles of each of these triangles is equal to two right angles (Th. xvii) : hence, the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point P is equal to four right angles (Th.... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...many of each as there are sides of the polygon: hence the sum of all the interior and exterior angles, is equal to twice as many right angles as the polygon' has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has... | |
 | Euclides - Geometry - 1853 - 334 pages
...regular polygons of the same number of sides, all the angles of each together with four right angles is equal to twice as many right angles as the polygon has sides ; and things that are equal to the same thing are equal to one another (Ax. i) : therefore the sum... | |
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... therefore the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles... 
