 | Robert Stewart (of Dundee.) - Arithmetic - 1871 - 248 pages
...the sum of these three numbers is the complete divisor, which multiply by the last quotient figure ; subtract the product from the dividend, and to the...remainder annex the next period for a new dividend, to which find a divisor as before, and proceed in the same manner till all the periods are exhausted.... | |
 | Henry Beadman Bryant, Emerson Elbridge White, Corydon Giles Stowell - Business mathematics - 1872 - 576 pages
...trial divisor; the sum will be the true divisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column 1st ; then add the square of the... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE,... | |
 | Philotus Dean - Arithmetic - 1874 - 472 pages
...divisor. Multiply this completed divisor by this last root figure; subtract the product, if possible, from the dividend, and to the remainder annex the next period for a new dividend. Double the whole root found, for a new trial divisor, and proceed as before, till all the periods have... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...the root and at the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...their sum will be the divisor completed. VI. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. VII. Thus proceed till the whole root is obtained. To find each successive trial divisor, proceed as... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...2d. The square of the last figure of the root. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend,...remainder annex the next period for a new dividend. Form, in the same manner, successive divisors, and find corresponding figures of the root ; being careful... | |
 | William Frothingham Bradbury - Algebra - 1877 - 302 pages
...right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, subtract the product from the dividend, and to the...remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to,the trial divisor, and bring down the next period... | |
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Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found, for a new divisor, and continue... 
