 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the...remainder annex the next period, for a NEW DIVIDEND. 1 V. To the last TRUE DIVISOR add the last figure of the root ; the sum, with a cipher annexed, will... | |
 | George Roberts Perkins - Arithmetic - 1850 - 356 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of the root for a new TRIAL DIVISOR,... | |
 | George Roberts Perkins - Arithmetic - 1851 - 356 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the...remainder annex the next period, for a NEW DIVIDEND. / V. To the last TRUE DIVISOR add the last figure of tht root; the sum, with a cipher annexed, will... | |
 | John Radford Young - 1851 - 266 pages
...divisor will thus be completed. Multiply this complete divisor by the term last placed in the quotient, subtract the product from the dividend, and to the remainder annex the two next terms of the polynomial, and a second dividend will be obtained. Proceed with this as with... | |
 | Daniel Leach - Arithmetic - 1851 - 280 pages
...divisor. Multiply the complete divisor by the last figure, and subtract the product from the partial dividend, and to the remainder annex the next period for a new partial dividend. To the complete divisor add the last figure of the root for a new trial divisor.... | |
 | Benjamin Greenleaf - Algebra - 1852 - 348 pages
...square of the last term to the term already in the divisor''s place, and the divisor will be completed. Multiply the complete divisor by the last term of...the product from the dividend, and to the remainder connect the three next terms, and proceed as before. EXAMPLES. 1. Find the cube root of a 3 +3a2J-|-3a6... | |
 | John Fair Stoddard - Arithmetic - 1852 - 320 pages
...divisor, 10 form the TRUE DIVISOR. Multiply the true divisor by the figure of the root last obtained ; subtract the product from the dividend, and to the remainder annex the next period for 0, NEW DIVIDEND. To the last divisor, add the last figure of the root (200+30) x4 43 200x30 To3 X o... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...root and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor,... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...and also on the right of the divisor. 4th. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found, for a new... | |
 | Charles Davies - 1852 - 344 pages
...root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root thus found, for a new trial... | |
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Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found, for a new divisor, and continue... 
