 | John Homer French - Arithmetic - 1872 - 348 pages
...already found, considered as tens, for the first trial divisor, by which divide the first dividend; and write the result for the second figure of the root,...figure of the root; subtract the product from the first dividend; and to the remainder annex the next period for a new dividend. IV. For the succeeding... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...and also place it at the right of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract...the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE,... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...result in the root and at the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete... | |
 | Philotus Dean - Arithmetic - 1874 - 472 pages
...divisor. Multiply this completed divisor by this last root figure; subtract the product, if possible, from the dividend, and to the remainder annex the next period for a new dividend. Double the whole root found, for a new trial divisor, and proceed as before, till all... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...their sum will be the divisor completed. VI. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. VII. Thus proceed till the whole root is obtained. To find each successive trial divisor,... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...root ; 2d. The square of the last figure of the root. Multiply the divisor thus increased by the last figure of the root; subtract the product from the...dividend, and to the remainder annex the next period for a new dividend. Form, in the same manner, successive divisors, and find corresponding figures of the... | |
 | Edward Brooks - Arithmetic - 1876 - 588 pages
...the root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for a trial divisor,... | |
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Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
