 | Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...Multiply tlie true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the number... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...to the trial divisor for a complete divisor ; multiply tlie complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period for a new dividend. V Multiply the last figure of the last complete divisor... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...the right of the partial divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial... | |
 | James Stewart Eaton - 1862 - 320 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...in the root, and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...correction, and the result will be the complete divisai'. V. Multiply the. complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring flown another period for a new dividend. VI. Add together the last complete divisor, the last... | |
 | James Stewart Eaton - Arithmetic - 1864 - 322 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
 | Edward Brooks - 1863 - 344 pages
...this write the square of the second figure; their sum will be the TRUE DIVISOR. IV. Multiply the true divisor by the second figure of the root, subtract the product from the dividend, and annex the next period for another dividend. Square the root now found, multiply by 300, and find the... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...annex the result both to the root and the divisor. 4. Multiply the divisor thus increased by the last figure of the root; subtract the product from the, dividend, and to the remaindet bring down the next period for a new dividend. 5. Double the whole root now found for a new... | |
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Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
